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ඉස්ලාම්-Cosmology1
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<blockquote data-quote="jamiezue" data-source="post: 14603478" data-attributes="member: 115905"><p><span style="font-size: 15px">ඉස්සෙල්ලාම අපි compton effect එක redshift eක නිපදවන්නේ කොහොමද කියලා බලමු...ඔයාට නොතේරුනා කියපු නිසා ඔන්න මම ඒක වෙන සමීකරනය දැම්මා..</span>බලන්න</p><p> z = HD/(1-HD/2)</p><p>z = red shift</p><p> D = distance of the object</p><p>H=Hubble's constant</p><p><span style="font-family: 'Symbol'">l </span>is the original wavelength</p><p></p><p>compton effect එකෙන් hubbles's constant එක මේ විදිහට ප්රකාශ කරන්න පුලුවන් </p><p></p><p>Hubble's law observes that the red shift, z, is proportional to the distance to the object: </p><p> z <span style="font-family: 'Symbol'">= Dl / l = </span>HD or, <span style="font-family: 'Symbol'">Dl = </span>HD<span style="font-family: 'Symbol'">l (1)</span> </p><p> where <span style="font-family: 'Symbol'">Dl </span>is the red shifted change in wavelength, <span style="font-family: 'Symbol'">l </span>is the original wavelength, D is the distance to the object, and H is "Hubble's constant" of proportionality (H is sometimes conventionally expressed as H/c for convenience for the Doppler interpretation). </p><p> If one interprets this law as being due to multiple Compton effect interactions of photons starting at the distance D and interacting with an intervening medium of free particles (such as electrons) of density <span style="font-family: 'Symbol'">r </span>particles per cubic centimeters, then the following calculations can be made: </p><p> <span style="font-family: 'Symbol'">Dl = (Dl</span>i)(Ni) (2) </p><p> where <span style="font-family: 'Symbol'">Dl</span>i is the shift per interaction given by the familiar Compton formula: </p><p> <span style="font-family: 'Symbol'">Dl</span>i = h (1 - cos <span style="font-family: 'Symbol'">q</span>)<span style="font-family: 'Symbol'"> / </span>mc <span style="font-family: 'Symbol'">(3)</span> </p><p> where h is Planck's constant, m is the mass of the particle (electron), c is the velocity of light, and <span style="font-family: 'Symbol'">q</span> is the angle of deflection of the photon velocity vector. Ni in equation 2 is the number of Compton interactions occurring, so that cos <span style="font-family: 'Symbol'">q</span> is the "average cos <span style="font-family: 'Symbol'">q</span>" observed over the large number of interactions involved. </p><p> Now: </p><p> Ni = (Nt)T (4) </p><p> That is, the number of interactions equals the integrated probability, Nt, that an interaction is occurring at any time, times the total time of travel, T, where </p><p> T = D / c (5) </p><p> </p><p> Now: </p><p> Nt = <span style="font-family: 'Symbol'">srl </span>c / <span style="font-family: 'Symbol'">l</span>c (6) </p><p> where <span style="font-family: 'Symbol'">s</span> is the Thomson cross section (in the case where the particle is the electron), and <span style="font-family: 'Symbol'">l</span>c = the Compton wavelength of the particle = h / mc </p><p> Thus, from equations 4, 5 and 6: </p><p> Ni = <span style="font-family: 'Symbol'">srl </span>c D / <span style="font-family: 'Symbol'">l</span>cc (7) </p><p> and from equations 2, 3 and 7 and substituting and canceling: </p><p> <span style="font-family: 'Symbol'">Dl = sr</span>(1 - cos <span style="font-family: 'Symbol'">q</span>)D<span style="font-family: 'Symbol'">l (8)</span> </p><p> Thus, from equations 1 and 8: </p><p> H = <span style="font-family: 'Symbol'">sr</span>(1 - cos <span style="font-family: 'Symbol'">q</span>) </p><p> This interesting result shows that the "large cosmological constant", H can be expressed in terms of the "smaller" Thomson cross-section constant so familiar in everyday physics of subatomic particles. This connection between the very large and the very small was first suggested by Dirac. </p><p> It should be noted that the <span style="font-family: 'Symbol'">l</span> in equations 6, 7 and 8 strictly speaking is not the original wavelength of the photon, but rather the wavelength at the time of the interaction. This wavelength varies from <span style="font-family: 'Symbol'">l</span> at the start to <span style="font-family: 'Symbol'">l</span> + <span style="font-family: 'Symbol'">Dl</span> at the end of the travel, so that the average wavelength should be <span style="font-family: 'Symbol'">l</span> + <span style="font-family: 'Symbol'">Dl</span>/2. This is a small correction for the observed cosmological (non-quasar) shifts where z is less than 1, the correction being less than the uncertainty in H and D. </p><p> Thus, when <span style="font-family: 'Symbol'">l</span> + <span style="font-family: 'Symbol'">Dl</span>/2 is substituted for <span style="font-family: 'Symbol'">l</span>, the result is: </p><p> z = HD/(1-HD/2), </p><p> which leads to correspondingly shorter distances for a given z than in the case that z = HD. These distance differences can be significant for larger z, resulting in a new form for Hubble's law. As better measurements are made of the redshift distance relationship, it should be theoretically possible to determine which relationship is the observed one. Preliminary evidence of such a deviation from z=HD is usually ascribed to deceleration or acceleration (depending on how you look at it) of the big bang, but is more logically described as being due to a Compton effect red shift. </p><p></p><p> මල්ලෙ පොල් නෙවේ<img src="/styles/default/xenforo/smilies/default/no.gif" class="smilie" loading="lazy" alt=":no:" title="No :no:" data-shortname=":no:" /></p></blockquote><p></p>
[QUOTE="jamiezue, post: 14603478, member: 115905"] [SIZE=4]ඉස්සෙල්ලාම අපි compton effect එක redshift eක නිපදවන්නේ කොහොමද කියලා බලමු...ඔයාට නොතේරුනා කියපු නිසා ඔන්න මම ඒක වෙන සමීකරනය දැම්මා..[/SIZE]බලන්න z = HD/(1-HD/2) z = red shift D = distance of the object H=Hubble's constant [FONT=Symbol]l [/FONT]is the original wavelength compton effect එකෙන් hubbles's constant එක මේ විදිහට ප්රකාශ කරන්න පුලුවන් Hubble's law observes that the red shift, z, is proportional to the distance to the object: z [FONT=Symbol]= Dl / l = [/FONT]HD or, [FONT=Symbol]Dl = [/FONT]HD[FONT=Symbol]l (1)[/FONT] where [FONT=Symbol]Dl [/FONT]is the red shifted change in wavelength, [FONT=Symbol]l [/FONT]is the original wavelength, D is the distance to the object, and H is "Hubble's constant" of proportionality (H is sometimes conventionally expressed as H/c for convenience for the Doppler interpretation). If one interprets this law as being due to multiple Compton effect interactions of photons starting at the distance D and interacting with an intervening medium of free particles (such as electrons) of density [FONT=Symbol]r [/FONT]particles per cubic centimeters, then the following calculations can be made: [FONT=Symbol]Dl = (Dl[/FONT]i)(Ni) (2) where [FONT=Symbol]Dl[/FONT]i is the shift per interaction given by the familiar Compton formula: [FONT=Symbol]Dl[/FONT]i = h (1 - cos [FONT=Symbol]q[/FONT])[FONT=Symbol] / [/FONT]mc [FONT=Symbol](3)[/FONT] where h is Planck's constant, m is the mass of the particle (electron), c is the velocity of light, and [FONT=Symbol]q[/FONT] is the angle of deflection of the photon velocity vector. Ni in equation 2 is the number of Compton interactions occurring, so that cos [FONT=Symbol]q[/FONT] is the "average cos [FONT=Symbol]q[/FONT]" observed over the large number of interactions involved. Now: Ni = (Nt)T (4) That is, the number of interactions equals the integrated probability, Nt, that an interaction is occurring at any time, times the total time of travel, T, where T = D / c (5) Now: Nt = [FONT=Symbol]srl [/FONT]c / [FONT=Symbol]l[/FONT]c (6) where [FONT=Symbol]s[/FONT] is the Thomson cross section (in the case where the particle is the electron), and [FONT=Symbol]l[/FONT]c = the Compton wavelength of the particle = h / mc Thus, from equations 4, 5 and 6: Ni = [FONT=Symbol]srl [/FONT]c D / [FONT=Symbol]l[/FONT]cc (7) and from equations 2, 3 and 7 and substituting and canceling: [FONT=Symbol]Dl = sr[/FONT](1 - cos [FONT=Symbol]q[/FONT])D[FONT=Symbol]l (8)[/FONT] Thus, from equations 1 and 8: H = [FONT=Symbol]sr[/FONT](1 - cos [FONT=Symbol]q[/FONT]) This interesting result shows that the "large cosmological constant", H can be expressed in terms of the "smaller" Thomson cross-section constant so familiar in everyday physics of subatomic particles. This connection between the very large and the very small was first suggested by Dirac. It should be noted that the [FONT=Symbol]l[/FONT] in equations 6, 7 and 8 strictly speaking is not the original wavelength of the photon, but rather the wavelength at the time of the interaction. This wavelength varies from [FONT=Symbol]l[/FONT] at the start to [FONT=Symbol]l[/FONT] + [FONT=Symbol]Dl[/FONT] at the end of the travel, so that the average wavelength should be [FONT=Symbol]l[/FONT] + [FONT=Symbol]Dl[/FONT]/2. This is a small correction for the observed cosmological (non-quasar) shifts where z is less than 1, the correction being less than the uncertainty in H and D. Thus, when [FONT=Symbol]l[/FONT] + [FONT=Symbol]Dl[/FONT]/2 is substituted for [FONT=Symbol]l[/FONT], the result is: z = HD/(1-HD/2), which leads to correspondingly shorter distances for a given z than in the case that z = HD. These distance differences can be significant for larger z, resulting in a new form for Hubble's law. As better measurements are made of the redshift distance relationship, it should be theoretically possible to determine which relationship is the observed one. Preliminary evidence of such a deviation from z=HD is usually ascribed to deceleration or acceleration (depending on how you look at it) of the big bang, but is more logically described as being due to a Compton effect red shift. මල්ලෙ පොල් නෙවේ:no: [/QUOTE]
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