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Message: <blockquote data-quote="JohnSnow" data-source="post: 28510010" data-attributes="member: 561961">meke uttare weradi.. man meken aran mulin beluwa. me calculation eka karama me uttare neweine enne(720 x 1080 x 24 x 25) / 8 = 648,000,000 meka tmai enna ona 58320000. prashne mu dena formula ekath dan harida kyana ekamu dan mata dena utarae <img src="/styles/default/xenforo/smilies/default/baffled.gif"  class="smilie" loading="lazy" alt=":baffled:" title="Baffled    :baffled:" data-shortname=":baffled:" />[CODE](i) To calculate the minimum bandwidth requirement for the effective transmission of the video, we need to determine the total number of bits per frame.With 24-bit color, the video is using 3 bytes (24 bits) per pixel.With a resolution of 720 by 1080, there are a total of 720 x 1080 = 777,600 pixels per frame.So, the total number of bits per frame is 777,600 x 24 = 18,874,400 bits.With a frame rate of 25 frames per second, the total number of bits per second is 18,874,400 x 25 = 471,860,000 bits per second.So, the minimum bandwidth requirement for effective transmission of the video is 471,860,000 bits per second.(ii) If the video is transmitted as monochrome, it will use 1 byte (8 bits) per pixel.So, the total number of bits per frame is 777,600 x 8 = 6,220,800 bits per frame.With a frame rate of 25 frames per second, the total number of bits per second is 6,220,800 x 25 = 155,520,000 bits per second.The ratio of bandwidth reduction is (471,860,000-155,520,000) / 471,860,000 = 0.67 or 67%[/CODE]</blockquote>

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