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<blockquote data-quote="imhotep" data-source="post: 27300697" data-attributes="member: 562115"><p>Good... That's why I didn;t reply. Both looks similar. Both Dual rank, same voltage and same timings. Should have worked unless a slot or a motherboard issue.</p><p>When it comes to mixing, you can t<strong>echnically mix speeds</strong>, BUT note that your DRAM would all run at the speed of the slowest module. For example, if you have a DDR3 1333MHz system and install a second module at 1600MHz, they would both run at the 1333MHz speed.</p><p>The same thing happens with modules that have <strong>different latencies</strong>. The system will run based on the module with the <strong>slowest timings </strong>as long as the motherboard supports.</p><p>You can even<strong> mix voltages - both will run at the higher voltage</strong> - eg if you have a 1.5v module in one slot and a dual voltage (1.35v/1.5v) model in the other, your system will run at 1.5v.</p><p>Having said that, when you mix brands, sometimes there could be the possibility of ending up with BSOD.</p></blockquote><p></p>
[QUOTE="imhotep, post: 27300697, member: 562115"] Good... That's why I didn;t reply. Both looks similar. Both Dual rank, same voltage and same timings. Should have worked unless a slot or a motherboard issue. When it comes to mixing, you can t[B]echnically mix speeds[/B], BUT note that your DRAM would all run at the speed of the slowest module. For example, if you have a DDR3 1333MHz system and install a second module at 1600MHz, they would both run at the 1333MHz speed. The same thing happens with modules that have [B]different latencies[/B]. The system will run based on the module with the [B]slowest timings [/B]as long as the motherboard supports. You can even[B] mix voltages - both will run at the higher voltage[/B] - eg if you have a 1.5v module in one slot and a dual voltage (1.35v/1.5v) model in the other, your system will run at 1.5v. Having said that, when you mix brands, sometimes there could be the possibility of ending up with BSOD. [/QUOTE]
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