Search
Search titles only
By:
Search titles only
By:
Log in
Register
Search
Search titles only
By:
Search titles only
By:
Menu
Install the app
Install
Forums
New posts
All threads
Latest threads
New posts
Trending threads
Trending
Search forums
What's new
New posts
New ads
New profile posts
Latest activity
Free Ads
Latest reviews
Search ads
Members
Current visitors
New profile posts
Search profile posts
Contact us
Latest ads
Premium Land with House for Sale
anil1961
Updated:
Today at 10:15 AM
AWS Certified Solutions Architect-Associate + AWS Certified Cloud Practitioner
Sanjeewani95
Updated:
Wednesday at 8:16 PM
🚀 එක පැකේජ් එකයි - මාසෙටම Unlimited Internet! 🌐
sayuru bandara
Updated:
Tuesday at 10:57 AM
🎬 CapCut Pro 1 Month Access! LKR 600
sayuru bandara
Updated:
Tuesday at 10:55 AM
🚀 Google One AI PRO Plan (Gemini Pro Activation) – 18 Months Access! LKR 2200
sayuru bandara
Updated:
Tuesday at 10:53 AM
Electronics
Vehicles
Property
Search
Reply to thread
Forums
General
ElaKiri Help
A/L මැත්ස් තනියම ඉගෙන ගන්නේ කොහොමද
Get the App
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Message
<blockquote data-quote="Lovtus" data-source="post: 28725261" data-attributes="member: 532745"><p>1.2) <strong>Q</strong><span style="font-size: 18px"><strong>uadratic function.</strong></span></p><p></p><p>A quadratic function is a type of function in which the highest degree of the variable is two. The general form of a quadratic function is:</p><p></p><p>f(x) = ax^2 + bx + c</p><p></p><p>where a, b, and c are constants. The graph of a quadratic function is a parabola, which can either be concave up or concave down, depending on the sign of the leading coefficient a.</p><p></p><p>The vertex of the parabola is the point where the function reaches its minimum or maximum value, and is given by the formula:</p><p></p><p>x = -b / 2a</p><p></p><p>y = f(-b / 2a)</p><p></p><p>The axis of symmetry is a vertical line that passes through the vertex, and is given by the equation:</p><p></p><p>x = -b / 2a</p><p></p><p>Quadratic functions can be used to model a variety of phenomena, such as the trajectory of a projectile, the shape of a bridge arch, or the growth of a population.</p><p></p><p>Here are some sample problems involving quadratic functions:</p><p></p><p>Problem 1: Find the vertex, axis of symmetry, and y-intercept of the quadratic function f(x) = x^2 - 4x + 5.</p><p></p><p>Solution: To find the vertex, we first need to find the x-coordinate, which is given by x = -b / 2a = -(-4) / 2(1) = 2. To find the y-coordinate, we substitute x = 2 into the function: f(2) = 2^2 - 4(2) + 5 = 1. Therefore, the vertex is (2, 1). The axis of symmetry is x = 2. To find the y-intercept, we set x = 0: f(0) = 0^2 - 4(0) + 5 = 5. Therefore, the y-intercept is (0, 5).</p><p></p><p>Problem 2: A ball is thrown upward from the ground with an initial velocity of 32 feet per second. The height h (in feet) of the ball at time t (in seconds) is given by the quadratic function h(t) = -16t^2 + 32t. Find the maximum height of the ball and the time it takes to reach that height.</p><p></p><p>Solution: The maximum height of the ball is reached at the vertex of the parabola. To find the vertex, we use the formula x = -b / 2a = -32 / 2(-16) = 1. The time it takes to reach the maximum height is 1 second. To find the maximum height, we substitute t = 1 into the function: h(1) = -16(1)^2 + 32(1) = 16. Therefore, the maximum height of the ball is 16 feet.</p></blockquote><p></p>
[QUOTE="Lovtus, post: 28725261, member: 532745"] 1.2) [B]Q[/B][SIZE=5][B]uadratic function.[/B][/SIZE] A quadratic function is a type of function in which the highest degree of the variable is two. The general form of a quadratic function is: f(x) = ax^2 + bx + c where a, b, and c are constants. The graph of a quadratic function is a parabola, which can either be concave up or concave down, depending on the sign of the leading coefficient a. The vertex of the parabola is the point where the function reaches its minimum or maximum value, and is given by the formula: x = -b / 2a y = f(-b / 2a) The axis of symmetry is a vertical line that passes through the vertex, and is given by the equation: x = -b / 2a Quadratic functions can be used to model a variety of phenomena, such as the trajectory of a projectile, the shape of a bridge arch, or the growth of a population. Here are some sample problems involving quadratic functions: Problem 1: Find the vertex, axis of symmetry, and y-intercept of the quadratic function f(x) = x^2 - 4x + 5. Solution: To find the vertex, we first need to find the x-coordinate, which is given by x = -b / 2a = -(-4) / 2(1) = 2. To find the y-coordinate, we substitute x = 2 into the function: f(2) = 2^2 - 4(2) + 5 = 1. Therefore, the vertex is (2, 1). The axis of symmetry is x = 2. To find the y-intercept, we set x = 0: f(0) = 0^2 - 4(0) + 5 = 5. Therefore, the y-intercept is (0, 5). Problem 2: A ball is thrown upward from the ground with an initial velocity of 32 feet per second. The height h (in feet) of the ball at time t (in seconds) is given by the quadratic function h(t) = -16t^2 + 32t. Find the maximum height of the ball and the time it takes to reach that height. Solution: The maximum height of the ball is reached at the vertex of the parabola. To find the vertex, we use the formula x = -b / 2a = -32 / 2(-16) = 1. The time it takes to reach the maximum height is 1 second. To find the maximum height, we substitute t = 1 into the function: h(1) = -16(1)^2 + 32(1) = 16. Therefore, the maximum height of the ball is 16 feet. [/QUOTE]
Insert quotes…
Verification
Hathara warak wissa keeyada? (Hathara wadi karanna 20)
Post reply
Top
Bottom