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A/L Chemistry help.simple question.but...
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<blockquote data-quote="mottaya" data-source="post: 15338988" data-attributes="member: 123465"><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">ek kala Na2S2O3 mol =0.01 moldm-3 * (4.5 * 10-3 moldm-3)</span></span></p><p> <span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">Na2S2O3 samaga prthikriya kala I2 mol <strong><span style="color: Blue">(1)</span></strong>=0.01 moldm-3 * (4.5 * 10-3 moldm-3) / 2 </span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">-------------------------------------------</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">50cm-3 kata ek kala I2 mol = 1g / 127gmol-1</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">so, 25cm-3 ka pawathi I2 mol (anumapanayata pera) <strong><span style="color: Blue">(2)</span></strong>= 1g / (127gmol-1 * 2)</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><strong><span style="color: Blue">(2)-</span></strong><strong><span style="color: Blue">(1)</span></strong> => CCl4 stharayata gaman kala I2 mol</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><span style="color: Blue"><strong>=(0.00196850 mol - 0.0000225mol)</strong></span></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><span style="color: Blue"><strong>=0.00194600 mol //</strong></span></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><span style="color: Blue"><strong></strong></span><strong></strong></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><strong><span style="color: Red">CCl4 parimaawa jala parimaawta samaana nam,</span></strong></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">Kd= (CCl4 stharaye I2 mol ganana) / (H2O stharaye I2 mol ganana)</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"> =0.00194600/0.0000225</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"> =86.48</span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px"><img src="/styles/default/xenforo/smilies/default/oo.gif" class="smilie" loading="lazy" alt=":oo:" title="Oo :oo:" data-shortname=":oo:" /></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">ජලය 50ක දිය කරලා එකෙන් 25ක් අරන් CCl4 එක්ක මිශ්ර කරලා ඒ 25ම අනුමාපනය කරනව kiyala haduwe.. anith widiyata(අයඩීන් ජලය 50ක ඩියකරලා CCl4 එක්ක කලවම් කරලා එකෙන් 25ක් ගන්නව) wena uththarayak enne..<img src="/styles/default/xenforo/smilies/default/oo.gif" class="smilie" loading="lazy" alt=":oo:" title="Oo :oo:" data-shortname=":oo:" /></span></span></p><p><span style="font-family: 'Verdana'"><span style="font-size: 12px">prashne upset hodatama..<img src="/styles/default/xenforo/smilies/default/dull.gif" class="smilie" loading="lazy" alt=":dull:" title="Dull :dull:" data-shortname=":dull:" /></span></span></p></blockquote><p></p>
[QUOTE="mottaya, post: 15338988, member: 123465"] [FONT=Verdana][SIZE=3]ek kala Na2S2O3 mol =0.01 moldm-3 * (4.5 * 10-3 moldm-3) Na2S2O3 samaga prthikriya kala I2 mol [B][COLOR=Blue](1)[/COLOR][/B]=0.01 moldm-3 * (4.5 * 10-3 moldm-3) / 2 ------------------------------------------- 50cm-3 kata ek kala I2 mol = 1g / 127gmol-1 so, 25cm-3 ka pawathi I2 mol (anumapanayata pera) [B][COLOR=Blue](2)[/COLOR][/B]= 1g / (127gmol-1 * 2) [B][COLOR=Blue](2)-[/COLOR][/B][B][COLOR=Blue](1)[/COLOR][/B] => CCl4 stharayata gaman kala I2 mol [COLOR=Blue][B]=(0.00196850 mol - 0.0000225mol) =0.00194600 mol // [/B][/COLOR][B] [COLOR=Red]CCl4 parimaawa jala parimaawta samaana nam,[/COLOR][/B] Kd= (CCl4 stharaye I2 mol ganana) / (H2O stharaye I2 mol ganana) =0.00194600/0.0000225 =86.48 :oo: ජලය 50ක දිය කරලා එකෙන් 25ක් අරන් CCl4 එක්ක මිශ්ර කරලා ඒ 25ම අනුමාපනය කරනව kiyala haduwe.. anith widiyata(අයඩීන් ජලය 50ක ඩියකරලා CCl4 එක්ක කලවම් කරලා එකෙන් 25ක් ගන්නව) wena uththarayak enne..:oo: prashne upset hodatama..:dull:[/SIZE][/FONT] [/QUOTE]
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