Reply to thread

Message: <blockquote data-quote="imhotep" data-source="post: 30123467" data-attributes="member: 562115">Te problem is you never made an effort and look forward for someone else to spoonfeed. This is not going to work unless you put your brain into gear.When you divide 2x^3+7x^2+13x-3 by (x+1)^2 the remainder is of the form R(x) = r1x + r0So 2x^3+7x^2+13x-3 = (x+1)^2 Q(x) + r1x + r0 ..........................(a)When x = -1, this becomes 2 (-1)^3 + 7 (-1)^2 + 13 (-1)  - 3 = 0 + r1 (-1) + r0So -2 + 7 -13 - 3 = -r1 + r0which is  - 11 = -r1 + r0   .....................(b)Now differentiate (a)6x^2+14x + 13 = 2 (x+1) Q(x) + (x+1)^2 Q'(x) +r1Now let x = -16 (-1)^2 + 14 (-1) + 13 = 0 + 0 + r1Therefore r1 = 5Hence from (b)  r0 = -6Hence the remainder when 2x^3+7x^2+13x-3 is divided by (x+1)^2 is = r1x + r0 = 5x - 6This is exactly what I wrote before without the spoonfeed to let you THINK.</blockquote>

Top Bottom