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c++ වල pass by value සහ pass by reference
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<blockquote data-quote="KingCM" data-source="post: 20481208" data-attributes="member: 482722"><p><span style="color: DarkSlateGray"><span style="font-size: 12px"><p style="text-align: center">If I tell you the URL, I'm<span style="color: DarkOrange"> passing by reference</span>. You can use that URL to see the same web page I can see. If that page is changed, we both see the changes. If you delete the URL, all you're doing is destroying your reference to that page - you're not deleting the actual page itself.</p></span></span></p><p style="text-align: center"><span style="color: DarkSlateGray"><span style="font-size: 12px"></p></span></span></p><p style="text-align: center"><span style="color: DarkSlateGray"><span style="font-size: 12px">If I print out the page and give you the printout, I'm <span style="color: Magenta">passing by value</span>. Your page is a disconnected copy of the original. You won't see any subsequent changes, and any changes that you make (e.g. scribbling on your printout) will not show up on the original page. If you destroy the printout, you have actually destroyed your copy of the object - but the original web page remains intact.</p><p></span></span></p><p style="text-align: center"><img src="http://i.stack.imgur.com/QdcG2.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p></blockquote><p></p>
[QUOTE="KingCM, post: 20481208, member: 482722"] [COLOR="DarkSlateGray"][SIZE="3"][CENTER]If I tell you the URL, I'm[COLOR="DarkOrange"] passing by reference[/COLOR]. You can use that URL to see the same web page I can see. If that page is changed, we both see the changes. If you delete the URL, all you're doing is destroying your reference to that page - you're not deleting the actual page itself. If I print out the page and give you the printout, I'm [COLOR="Magenta"]passing by value[/COLOR]. Your page is a disconnected copy of the original. You won't see any subsequent changes, and any changes that you make (e.g. scribbling on your printout) will not show up on the original page. If you destroy the printout, you have actually destroyed your copy of the object - but the original web page remains intact.[/CENTER][/SIZE][/COLOR] [CENTER][IMG]http://i.stack.imgur.com/QdcG2.gif[/IMG][/CENTER] [/QUOTE]
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