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ElaKiri Talk!
Can you solve this ? - Creative Thinkers Only !!!!!!!
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<blockquote data-quote="MihiCherub" data-source="post: 15265666" data-attributes="member: 238676"><p>correct... <span style="color: Indigo"><em><img src="http://www.elakiri.com/forum/images/icons/sq/11.gif" alt="" class="fr-fic fr-dii fr-draggable " style="" /></em></span></p><p><span style="color: Indigo"><em></em></span></p><p><span style="color: Indigo"><em>Average rate is not the average of the rates,</em></span> the distance does not need to be known. Where a and b are the two rates, the average rate can be shown to be </p><p>2ab/(a + b), so 2(20)(60)/(20 + 60) = 30.</p><p></p><p>Average rate = Total distance/Total time. </p><p>Let’s say the distance is <span style="color: Red">D</span> one way. Then the total distance is <span style="color: Red">2D</span>. </p><p>Let’s say the time the car travels 20 mph is <span style="color: Red">t</span> and the time the car travels 60 mph is <span style="color: Red">T</span>. </p><p>Then from the formula Rate × Time = Distance, 20 × t = D and 60 × T = D.</p><p>This gives you t = D/20 and T = D/60. </p><p></p><p>So the total time is,</p><p>t + T = D/20 + D/60. This is equal to t + T = 80D/1,200 = D/15.</p><p></p><p>So the average rate = 2D/(t + T) = 2D/(D/15) = 30.</p></blockquote><p></p>
[QUOTE="MihiCherub, post: 15265666, member: 238676"] correct... [COLOR=Indigo][I][IMG]http://www.elakiri.com/forum/images/icons/sq/11.gif[/IMG] Average rate is not the average of the rates,[/I][/COLOR] the distance does not need to be known. Where a and b are the two rates, the average rate can be shown to be 2ab/(a + b), so 2(20)(60)/(20 + 60) = 30. Average rate = Total distance/Total time. Let’s say the distance is [COLOR=Red]D[/COLOR] one way. Then the total distance is [COLOR=Red]2D[/COLOR]. Let’s say the time the car travels 20 mph is [COLOR=Red]t[/COLOR] and the time the car travels 60 mph is [COLOR=Red]T[/COLOR]. Then from the formula Rate × Time = Distance, 20 × t = D and 60 × T = D. This gives you t = D/20 and T = D/60. So the total time is, t + T = D/20 + D/60. This is equal to t + T = 80D/1,200 = D/15. So the average rate = 2D/(t + T) = 2D/(D/15) = 30. [/QUOTE]
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