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Message: <blockquote data-quote="koondeGoda" data-source="post: 7263166" data-attributes="member: 61636">To validate numbers , make a call for  this function in your if condition.  pass the user input (s) . hope this helps[PHP]<script type="text/javascript">function isInteger(s){   var i;    for (i = 0; i < s.length; i++)    {           // Check that current character is number.        var c = s.charAt(i);        if (((c < "0") || (c > "9"))) return false;    }    // All characters are numbers.    return true;}</script>[/PHP]OK! here i extended truth4L's code <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" /> [PHP]<html>    <head>        <title></title>        <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">        <script language="Javascript" type="text/javascript">            function validate(){                var nic_no = document.getElementById('nic').value;                                if(nic_no.length == 10 && nic_no.charAt(9)=='V' && isInteger(nic_no.substring(0,9) )){                    alert("NIC number is Valid");                }else{                    alert("NIC number is Invalid");                }                            }                        function isInteger(s)             {   var i;                 for (i = 0; i < s.length; i++)                 {                    // Check that current character is number.                     var c = s.charAt(i);                     if (((c < "0") || (c > "9"))) return false;                 }                 // All characters are numbers.                 return true;             }        </script>    </head>    <body>        NIC : <input type="text" id="nic">        <input value="Check" id="check" type="button" onclick="validate()">    </body></html>[/PHP]</blockquote>

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