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<blockquote data-quote="the_myth" data-source="post: 4772355" data-attributes="member: 191444"><p>Here is the first Challenge from me.</p><p></p><p><span style="font-size: 12px"><span style="color: Blue">If </span></span></p><p><span style="font-size: 12px"><span style="color: Blue">x= sec<em><strong>a</strong></em> - tan<em><strong>a</strong></em> & (<em><strong>a</strong></em> is a variable)</span></span></p><p><span style="font-size: 12px"><span style="color: Blue"> y= cosec<em><strong>a</strong></em>-cot<em><strong>a</strong></em></span></span></p><p><span style="font-size: 12px"><span style="color: Blue"></span></span></p><p><span style="font-size: 12px"><span style="color: Blue"></span></span></p><p><span style="font-size: 12px"><span style="color: Blue">Then prove that</span></span><span style="color: Blue"></span></p><p><span style="color: Blue"></span></p><p><span style="color: Blue"></span> <ol> <li data-xf-list-type="ol"><span style="font-size: 12px"><span style="color: Blue">x= (y+1)/(y-1) </span></span></li> <li data-xf-list-type="ol"><span style="font-size: 12px"><span style="color: Blue">y=(1+x)/1-x)</span></span></li> <li data-xf-list-type="ol"><span style="font-size: 12px"><span style="color: Blue">xy+x-y+1=0</span></span></li> </ol><p>May be it's easy for some Ek members, but try it.</p></blockquote><p></p>
[QUOTE="the_myth, post: 4772355, member: 191444"] Here is the first Challenge from me. [SIZE=3][COLOR=Blue]If [/COLOR][/SIZE] [SIZE=3][COLOR=Blue]x= sec[I][B]a[/B][/I] - tan[I][B]a[/B][/I] & ([I][B]a[/B][/I] is a variable) y= cosec[I][B]a[/B][/I]-cot[I][B]a[/B][/I] Then prove that[/COLOR][/SIZE][COLOR=Blue] [/COLOR][LIST=1] [*][SIZE=3][COLOR=Blue]x= (y+1)/(y-1) [/COLOR][/SIZE] [*][SIZE=3][COLOR=Blue]y=(1+x)/1-x)[/COLOR][/SIZE] [*][SIZE=3][COLOR=Blue]xy+x-y+1=0[/COLOR][/SIZE][/LIST]May be it's easy for some Ek members, but try it. [/QUOTE]
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