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<blockquote data-quote="Pura Pagal" data-source="post: 2399813" data-attributes="member: 97277"><p><span style="font-size: 12px"><span style="color: Black">I have followed this thread closely and with great interest, and in my opinion (as I do not understand any of the SL Languages) Senior Member: senewimala1988 has all of them correct except for the last one, which he could have explained a bit more. Here is how:</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">(5 - 2x) / (2x - 5)</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">Multiply and divide both Numerator and Denominator by -1 (since multiplying and dividing by same number will have no affect)</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">= -1 * (5 - 2x) / {-1 * (2x - 5)}</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">Solving the denominator only</span></span></p><p><span style="font-size: 12px"><span style="color: Black">= -1 * (5 - 2x) / (-2x + 5)</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">Rearranging the denominator only</span></span></p><p><span style="font-size: 12px"><span style="color: Black">= -1 * (5 - 2x) / (5 - 2x)</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">Now canceling out (5 - 2x) from both numerator and denominator</span></span></p><p><span style="font-size: 12px"><span style="color: Black">= -1</span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black"><strong><span style="color: Red"><u>CAUTION:</u> The value of x could not be determined in any of the problems that are mentioned as these are algebraic expressions and NOT equation</span></strong></span></span></p><p><span style="font-size: 12px"><span style="color: Black"></span></span></p><p><span style="font-size: 12px"><span style="color: Black">If you need further details please send a PM</span></span></p></blockquote><p></p>
[QUOTE="Pura Pagal, post: 2399813, member: 97277"] [SIZE=3][COLOR=Black]I have followed this thread closely and with great interest, and in my opinion (as I do not understand any of the SL Languages) Senior Member: senewimala1988 has all of them correct except for the last one, which he could have explained a bit more. Here is how: (5 - 2x) / (2x - 5) Multiply and divide both Numerator and Denominator by -1 (since multiplying and dividing by same number will have no affect) = -1 * (5 - 2x) / {-1 * (2x - 5)} Solving the denominator only = -1 * (5 - 2x) / (-2x + 5) Rearranging the denominator only = -1 * (5 - 2x) / (5 - 2x) Now canceling out (5 - 2x) from both numerator and denominator = -1 [B][COLOR=Red][U]CAUTION:[/U] The value of x could not be determined in any of the problems that are mentioned as these are algebraic expressions and NOT equation[/COLOR][/B] If you need further details please send a PM[/COLOR][/SIZE] [/QUOTE]
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