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Message: <blockquote data-quote="cbpower" data-source="post: 4544375" data-attributes="member: 107612">MyAnswers <img src="/styles/default/xenforo/smilies/default/happy.gif"  class="smilie" loading="lazy" alt=":)" title="Happy    :)" data-shortname=":)" />a) Probability of getting 3 the first no- 1/10 Probability of getting 2 as the second no- 1/10Probability of getting 1 as the third no-1/10 So the probability of getting 321= 1/10 * 1/10 * 1/10 = (1/10)^3 = 1/1000(Method used- tree diagram) b) 1/1000 (only 1 customer will get the no assuming the no will not repeat for a day) c) 1st, 2nd and 3rd Digits should not have 7s. So the probability is 9/10 * 9/10 * 9/10 = (9/10 )^3=729/1000 d) you will get 7s when -1st digit is 7 (Assume other digits are not 7s)2nd digit is 7 (Assume " " " " )3rd digit is 7 (Assume " " " " )Also 1 st & 2nd digits are 7, 2nd and 3rd digits are 7, 1st & 3rd digits are 7 or all digits are 7. So there are seven (7) possibilities of getting 7So the probability is = 7/1000</blockquote>

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