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Message: <blockquote data-quote="blastxp" data-source="post: 4556566" data-attributes="member: 39270">koi ekath ekai bari welawata mokekwath ne mamath ookata answer hoyanawa here is the answer for 1 Q•    Since the number is selected independently of the others 111 is a valid number. Also I am assuming that 123 is different form 321There are 10 number to pick from (0, 1, ... 9)There are 3 digitsSo 10 ways to pick the first10 ways to pick the second10 ways to pick the thirdThere is 1 way to pick 321 out of 1000. So 1/1000b. Assuming that each number is different, no two customers can get 123.So 1000 customers 1000 numbers . The probability that some one wins is 1.How many ways can the first number not be 7 = 9How many ways can the 2nd number not be 7 = 9How many ways can the 3rd number not be 7 = 9So there are 9*9*9 / 1000 ways of not having the number have any sevensd) Prob that is has at least 1 seven is 1 - P( no sevens) =1 - 9*9*9/1000yahoo answer  eke dala thibba kalin</blockquote>

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