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Message: <blockquote data-quote="rclakmal" data-source="post: 8044619" data-attributes="member: 98858"><p>I think you have done the theorem ( I dont remember the name ) which says when there are <strong>n</strong> different objects you can have <strong>n!</strong> <strong>permutations</strong> .And in that n objects if there are <strong>p</strong> objects of 1 type and <strong>q</strong> number of 2nd type.(where p+q=n) then you can have <strong>n!/(p!*q!) </strong>.</p><p></p><p>So here are the possibilities</p><p></p><p>1. 2 girls 3 boys </p><p>    permutations =5!/(2!*3!)=10</p><p></p><p>2. 3 girls 2 boys </p><p>    permutations =5!/(3!*2!)=10</p><p></p><p>3. 4 girls 1 boy </p><p>    permutations =5!/(4!*1!)=5</p><p></p><p>4. 5 girls 0 boys </p><p>    permutations =5!/(2!*3!)=1</p><p></p><p>So all permutations =10+10+5+1=26</p><p>Your answer=5/26</p><p></p><p>Ask if you need any further help !</p></blockquote><p></p>

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