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Message: <blockquote data-quote="amilabanuka" data-source="post: 16781813" data-attributes="member: 5836">Yes. it is not the pass by reference in C/C++, that is a different thing. In java objects are passed using references and the references is passed by value. So yes Java is Pass-by-value language. but when passing an object the value of the object reference is passed. so both sender and receiver points to the same object in the memory. If the object is pass-by-value then the receiving party should have their own copy of the object. that is not the case with java. this is bit tricky.the pointer value of the object which lives in the heap is given to another variable. so both original variable and the new variable which got the pointer holds the reference (pointer to the memory in the heap). the object reference is passed by value. so the reference to an object which lives in the heap is passed to the method by passing the memory address of the object. So when considering how the receiving party got hold of the object. it receives the object via getting the location of the object as a value in the parameter. Java cannot pass the actual object (as in C/C++) as it only supports passing values. but eventually the the receiving party gets a reference (which was passed as a value) to the object (not the object itself).edit: <a href="http://stackoverflow.com/questions/40480/is-java-pass-by-reference-or-pass-by-value" target="_blank">http://stackoverflow.com/questions/40480/is-java-pass-by-reference-or-pass-by-value</a> has some good explanation.</blockquote>

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