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Message: <blockquote data-quote="Qrious" data-source="post: 15624059" data-attributes="member: 421312"><img src="/styles/default/xenforo/smilies/default/rofl.gif"  class="smilie" loading="lazy" alt=":rofl:" title="ROFL    :rofl:" data-shortname=":rofl:" />ah hankok koluwa mama ube mahaloku gana haduwa. <img src="/styles/default/xenforo/smilies/default/lol.gif"  class="smilie" loading="lazy" alt=":lol:" title="LOL    :lol:" data-shortname=":lol:" />uba hithan inne ube solution eka patta efficient kiyala neda? <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" /> mama mage solution eka danna kalin ube solution ekama thawa tikak efficient karala innamko <img src="/styles/default/xenforo/smilies/default/lol.gif"  class="smilie" loading="lazy" alt=":lol:" title="LOL    :lol:" data-shortname=":lol:" />onna ube gon solution eka <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />[CODE]#include <stdio.h>void main(){int a=1,b=2,c,d,e=2; for(c=1;c<20;c++){     d=b;     b=a+b;     a=d;     if(c==3)     {        e=e+b;        c=0;        printf("%d %d\n",b,e);      }     if(b>4000000)        break;   }}[/CODE]menna uba karala thiyena gon wada tika:1. for loop eke c < 20 kiyana condition eken kisima wadak wenne na. eka galawala puke gaha ganin. loop eka execute wena warayak gane ea condition eka check karanawa eken efficiency eka adu wenawa <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />2. uba kiwwa neda even numbers check karanna modulus operator eka pawichchi kale na kiyala. itin harako uba wena operators walin karala thiyenneth ea wademane. <img src="/styles/default/xenforo/smilies/default/lol.gif"  class="smilie" loading="lazy" alt=":lol:" title="LOL    :lol:" data-shortname=":lol:" /> onna balapan:[CODE]                                if (c == 3)                {                    e = e + b;                    c = 0;                    printf("%d %d\n", b, e);                }[/CODE]okama ubata mehema liyanna thibbane:[CODE]                                if (c % 3 == 0)                {                    e = e + b;                    printf("%d %d\n", b, e);                }[/CODE]modulus operator eka nathuwath uba operators okkoma 4 k pawichchi karala thiyenawa. modulus operator eka thibbath okkoma operators 4 k pawichchi wenawa. itin uba modulus operator eka pawichchi kale na kiyala efficiency eke kisima wadi weemak wela na. <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />3. uba karala thiyena anith moda wade thamai result eka calculate karana asse print karanna yana eka. printf function eka implement karanna liyapu code goda dakkoth thota kalanthe dai <img src="/styles/default/xenforo/smilies/default/lol.gif"  class="smilie" loading="lazy" alt=":lol:" title="LOL    :lol:" data-shortname=":lol:" />. anith eka uba deepu prashne ubama hariyata kiyawala na. eke ahala thiyenne awasana uththare witharai. intermediate values print karanna kiyala na <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />menna ubema solution eka ubata wada efficient karala mama hadapu hati <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />[CODE]#include <stdio.h>void main(){int a=1,b=2,c,d,e=2; for(c=1;;c++){     d=b;     b=a+b;     a=d;     if(c%3 == 0)     {        e=e+b;     }     if(b>4000000)        break;   }   printf("%d %d\n", b, e);}[/CODE]menna mage solution eka. matanam even numbers check karanna modulus operator ekawath ubata wage == (comparision operator) ekakwath one une na <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" /> . mage solution eka ube ekata wada godak efficient. ube solution eke loop eka 31 parak execute wenawa. mage solution eke loop eka execute wenne 12 parai. <img src="/styles/default/xenforo/smilies/default/P.gif"  class="smilie" loading="lazy" alt=":P" title=":P    :P" data-shortname=":P" />(C# walin liwwe. ubata mole kaladak thiyenam meka lesiyenma C walata convert karanna puluwan wenna ona)mata anithimata kiyanna thiyenne mechcharai. uba uba ganama ali oluwen hithan hitiyata uba hithana tharam waddek nemei uba. Thamange tharama therum aran wadiya sadda danne nathuwa wada karapan. Dan balapan mama witharak nemei thawa kee denek kiyanawada uba gona kiyala. Anika software company wala interview waladi ali oluwen inna unwa kelinma kapala danawa. mokada un ekka wena katawath ekata wada karanna bari nisa. eka hinda ali oluwa bassagena thamange aththa thaththwaya therum aragena wada karapan. </blockquote>

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