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Message: <blockquote data-quote="imhotep" data-source="post: 28730929" data-attributes="member: 562115">Just note that  F = ma is not an exact equation. It's different to what you learn in year 9 or 10. Te more general form of the equation is F= dp/dt which is the rate of change of momentum - and is the correct form of the 2nd law.The above brings us another form of the equation  F = d(mv)/dtIf we assume the mass is constant, then we can rewrite the above as F = m dv/dtSince dv/dt is the acceleration then we get F = maThis holds correct ONLY for Classical physics.When you consider relativistic conditions, then the momentum is not simply mv but takes a different form - which isp = m0 v / SQR (1 - (v/c)^2) where m0 is the rest mass and c is the speed of light.</blockquote>

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