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Message: <blockquote data-quote="C.I.D" data-source="post: 13106543" data-attributes="member: 386756">ok...this may be correct..(but check if it's wrong)initial S solution contains less water soluble salt.therfore u hav to get H+ ions giving from both HCl and MCl2 salt..first cal pka1 from pkb2 AND cal pka2 from pkb1..then calculate H+ from MCl2 salt(by neglecting Ka2 coz it's very low) and get the pH..(u knw the equations)..2.This is strong acid-strong base titration but consider the concentration of NaOH is 0.1M AND S solution is=(0.05M) but also consider pH value(from both HCl and MCl2)</blockquote>

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