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Write a C++ Program...
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<blockquote data-quote="viraj_slk" data-source="post: 7372505" data-attributes="member: 51932"><p><span style="font-size: 12px">Here ! the code is right in front of you bro! why are u asking for more? you only have to correct the sytaxes according to C++ now. don't expect me to go through C++ syntaxs now and do it. it's ur job. <img src="/styles/default/xenforo/smilies/default/happy.gif" class="smilie" loading="lazy" alt=":)" title="Happy :)" data-shortname=":)" /></span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px">again the code is:</span></p><p><span style="font-size: 12px">[CODE]</span></p><p><span style="font-size: 12px">arr[] = {1, 2, 3, 4, 5} // or whatever other numbers u want. this is our original array.</span></p><p><span style="font-size: 12px">new_arr[]; // new array we are going to build</span></p><p><span style="font-size: 12px">int p; // the new position for each element in array</span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px">for(i= 0; i < n; i++){</span></p><p><span style="font-size: 12px"> p = (i + x)%n; // remember n is the number of values in array & x is user input value</span></p><p><span style="font-size: 12px"> </span></p><p><span style="font-size: 12px"> new_arr[p] = arr[i]; </span></p><p><span style="font-size: 12px">} </span></p><p><span style="font-size: 12px">[/CODE]</span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px">now 'new_arr' array contains the shifted numbers. This is the code. Use ur syntaxes to write it in whatever language u want.</span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px">to answer ur questions:</span></p><p><span style="font-size: 12px">no u don't have to give a size to the array. but if you want, give it the same size as the original. it's going to contain the same number of elements any way. </span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px">use the for loop to fill the new array using the formula inside it that I described to you in the previous post.</span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px"></span></p><p><span style="font-size: 12px"></span></p></blockquote><p></p>
[QUOTE="viraj_slk, post: 7372505, member: 51932"] [SIZE="3"]Here ! the code is right in front of you bro! why are u asking for more? you only have to correct the sytaxes according to C++ now. don't expect me to go through C++ syntaxs now and do it. it's ur job. :) again the code is: [CODE] arr[] = {1, 2, 3, 4, 5} // or whatever other numbers u want. this is our original array. new_arr[]; // new array we are going to build int p; // the new position for each element in array for(i= 0; i < n; i++){ p = (i + x)%n; // remember n is the number of values in array & x is user input value new_arr[p] = arr[i]; } [/CODE] now 'new_arr' array contains the shifted numbers. This is the code. Use ur syntaxes to write it in whatever language u want. to answer ur questions: no u don't have to give a size to the array. but if you want, give it the same size as the original. it's going to contain the same number of elements any way. use the for loop to fill the new array using the formula inside it that I described to you in the previous post. [/SIZE] [/QUOTE]
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