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Message: <blockquote data-quote="rajitha_ks" data-source="post: 8016085" data-attributes="member: 162025">wtf dudeaccording to ur stepslets follow the above steps for the arbitrary number "x" and see1) x2) x*33) x*3 + 3 = 3(x+1)4)3*3(x+1) = 9(x+1)now you can see that whatever the number you pick you'll end up with a multiple of 9!now these are the multiples of nine 9  -> 9+0 = 918 -> 1+8 = 927 -> 2+7 = 936 -> 3+6 = 945 -> 4+5 = 954 -> 5+4 = 963 -> 6+3 = 9...now if you add the first two digits of all these numbers you'll end up with nine<img src="/styles/default/xenforo/smilies/default/yes.gif"  class="smilie" loading="lazy" alt=":yes:" title="Yes    :yes:" data-shortname=":yes:" />so nomatter what the number you initially pick, you are bound to end up with 9, which is Nalith</blockquote>

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