Oh I see why you failed in your invasion if so..
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ECON danna kollo mehe warella... HELP
- Thread starter maxXxa
- Start date
Oh I see why you failed in your invasion if so..
වැරදියි,,, වැරදියි,, හැමෝම වැරදියි,,
AC= Q^2 - 4Q + 214
Quantity එක 10 යි නේ,,,
ඉතින් units 10 ක Total Cost eka = 10 (Q^2 - 4Q + 214)
TC = 10Q^2 - 40Q - 2140
Total Cost function එකෙන් Marginal Cost Function එක ගන්න නම් Total Cost Function එක අවකලනය කරන්න ඕනා.. උසස් පෙළ ගණිත අංශයෙන් කරපු කස්ටිය සීන් එක දන්නවා ඇතිනේ??
ඉතින් එහෙම අවකලනය කරාම එන MC Function එක;
MC = 20Q - 40
ඕක තමා නිවැරදි පිළිතුරු function එක..
දැන් ඉතින් Quantity එක ඕකට දාන්න..
MC = 20Q - 40
MC = 20(10) - 40
MC = 160
AC= Q^2 - 4Q + 214
Quantity එක 10 යි නේ,,,
ඉතින් units 10 ක Total Cost eka = 10 (Q^2 - 4Q + 214)
TC = 10Q^2 - 40Q - 2140
Total Cost function එකෙන් Marginal Cost Function එක ගන්න නම් Total Cost Function එක අවකලනය කරන්න ඕනා.. උසස් පෙළ ගණිත අංශයෙන් කරපු කස්ටිය සීන් එක දන්නවා ඇතිනේ??
ඉතින් එහෙම අවකලනය කරාම එන MC Function එක;
MC = 20Q - 40
ඕක තමා නිවැරදි පිළිතුරු function එක..
දැන් ඉතින් Quantity එක ඕකට දාන්න..
MC = 20Q - 40
MC = 20(10) - 40
MC = 160
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Oyaa oya karana de waradeee. Q=10 lakshayedi witharak awakalana sangunakaya ganna behene
Oya widiyata karanawanam
TC = (Q^2 - 4Q + 214)*Q
= Q^3 - 4Q^2 + 214Q
d(TC)/dQ = MC = 3Q^2 - 8Q + 214
Then MC at 10 = 3*100 - 80 + 214 = 434 ???????????
Ape kramei me kramei wenas. Eka hinda 1 kramene hari
. Mama hari krame mokadda saha anith eke waradda mokadda kiyala thawa balala kiyannam. Eka paaratama meter wenne nehe. Thanks for pointing this out Pathum_madu
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Naha.Oka waradi. Ehema baluwoth hama output level eke ma 10 units walata ena cost structure eka ma ne enne. VC is non-linear
hmm
Sorry Mal Aiya but you are wrong. It does not have to be linear. See http://en.wikipedia.org/wiki/Marginal_cost Nobody is completely right or wrong at this point. Damn this shouldn't be such a big deal
I think I got it.
In the very first answer (409) we assumed (incorrectly) the Total Cost formula to be linear
Because we thought MC = [ TC(10) - TC(9) ]/1 . See that this is like taking the gradient of a straight line?
But turns out this is not the case. TC is NOT a linear equation. So to get the proper gradient we HAVE to calculate the derivative.
The derivative will yield the MC, and substituting 10 will give the answer.
So in short, 434 is the correct answer.
The reason we got 409 earlier is because the assumption that TC is linear is not a bad assumption. So we get an answer close to the real one.
P.S - sorry for typing all this in English. I find typing in Sinhala a bit of a pain. e wunaata mata sinhala puluwan
In the very first answer (409) we assumed (incorrectly) the Total Cost formula to be linear
Because we thought MC = [ TC(10) - TC(9) ]/1 . See that this is like taking the gradient of a straight line?
But turns out this is not the case. TC is NOT a linear equation. So to get the proper gradient we HAVE to calculate the derivative.
The derivative will yield the MC, and substituting 10 will give the answer.
So in short, 434 is the correct answer.
The reason we got 409 earlier is because the assumption that TC is linear is not a bad assumption. So we get an answer close to the real one.
P.S - sorry for typing all this in English. I find typing in Sinhala a bit of a pain. e wunaata mata sinhala puluwan
I think I got it.
In the very first answer (409) we assumed (incorrectly) the Total Cost formula to be linear
Because we thought MC = [ TC(10) - TC(9) ]/1 . See that this is like taking the gradient of a straight line?
But turns out this is not the case. TC is NOT a linear equation. So to get the proper gradient we HAVE to calculate the derivative.
The derivative will yield the MC, and substituting 10 will give the answer.
So in short, 434 is the correct answer.
The reason we got 409 earlier is because the assumption that TC is linear is not a bad assumption. So we get an answer close to the real one.
P.S - sorry for typing all this in English. I find typing in Sinhala a bit of a pain. e wunaata mata sinhala puluwan
But MC is simply the change in TC / change in output, right?
The linear and non-linear attribute of TC will not affect this example as our change in Q, is 1. So either way, it should be only the difference in the two TC's, right?.
hayyo;;
සමාවෙන්න ඕන හැමෝම;
AC= Q^2 - 4Q + 214
TC = Q^3 - 4Q^2 + 214Q
MC = 3Q^2 - 8Q + 214
Q = 10
MC = 3(10^2) - 8(100) + 214
434
සමාවෙන්න ඕන හැමෝම;
AC= Q^2 - 4Q + 214
TC = Q^3 - 4Q^2 + 214Q
MC = 3Q^2 - 8Q + 214
Q = 10
MC = 3(10^2) - 8(100) + 214
434
I think I got it.
In the very first answer (409) we assumed (incorrectly) the Total Cost formula to be linear
Because we thought MC = [ TC(10) - TC(9) ]/1 . See that this is like taking the gradient of a straight line?
But turns out this is not the case. TC is NOT a linear equation. So to get the proper gradient we HAVE to calculate the derivative.
The derivative will yield the MC, and substituting 10 will give the answer.
So in short, 434 is the correct answer.
The reason we got 409 earlier is because the assumption that TC is linear is not a bad assumption. So we get an answer close to the real one.
P.S - sorry for typing all this in English. I find typing in Sinhala a bit of a pain. e wunaata mata sinhala puluwan
Meka hari;;; 434 answer eka,, hadana steps tika man daala athi,,, Thanks hamotama,,
Meka hari;;; 434 answer eka,, hadana steps tika man daala athi,,, Thanks hamotama,,
මේක යකාගේ කතාවක්නේ! උඹේ වැරැද්ද කියලා හදන විදියත් දැම්මට පස්සේ හදන ක්රමේ දැම්මේ උඹ්යි කියලා කියන්නේ! මම කලින් කරපු එක එහෙමම කරලා ඊට පස්සේ තමන් ම කරා වගේ කියනවා
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No MC is NOT simply ( change in TC / change in output ). It is d(TC)/ dQ, which simplifies to ( change in TC / change in output ) when TC is linear.
Remember when acceleration is linear we say (pasu pravegaya - pera pravegaya)/kaalaya, but if acceleration is not linear we say dV/dt. Something like that.
But it beats me why they have defined MC like that. It seems much more practical to simply say the increase in cost because we produce an additional unit.
Oyaa oya karana de waradeee. Q=10 lakshayedi witharak awakalana sangunakaya ganna behene
Oya widiyata karanawanam
TC = (Q^2 - 4Q + 214)*Q
= Q^3 - 4Q^2 + 214Q
d(TC)/dQ = MC = 3Q^2 - 8Q + 214
Then MC at 10 = 3*100 - 80 + 214 = 434 ???????????
Ape kramei me kramei wenas. Eka hinda 1 kramene hari
Thanks for pointing this out Pathum_madu
Umba hari machan;; dan umbe post eka dakke;;
Quantity eka deepu nisa poddak awul giya,, Q nodi Profit max karanna kiwwanam OK,, Anyway meka AL gaanak nemei,, Chartered Foundation gaanak,,
මේක යකාගේ කතාවක්නේ! උඹේ වැරැද්ද කියලා හදන විදියත් දැම්මට පස්සේ හදන ක්රමේ දැම්මේ උඹ්යි කියලා කියන්නේ! මම කලින් කරපු එක එහෙමම කරලා ඊට පස්සේ තමන් ම කරා වගේ කියනවා
කවුද බන් කිව්වේ මම දැම්මේ කියල,, මන් කිව්වේ Answer එක ලියන්න ඕන steps ටික දැම්ම කියල,, බලන එකාට තේරනව idea එක උඹේ කියල..
OK Sorry Bannata.
Umba awakalana kathaawa kiyanakam mata nikamatawath hitune nehe. E wunaata meka dapu kena awakalanaya ehema dannawada danne nehe. Uthtarenam den hari ethi .
Its like this, if this production function was linear, then we would have got the MC exactly because it is the same at every point. When you differentiate and get a value, it is the difference from 9.999999999999.... to the 10th point. That is mathematically therefore correct. But in economics, businessemen need change from unit to unit as there is no part of a unit produced or anything. So our method of finding MC is from the 9th to 10th unit Only.
The method that gives us 409 is known as mid-point formula method, where we simply find the linear change from two distant points, but when you draw a curve, the change to the 10th point is not from 9, but from 9.9999999999...(recurring); this method is known as Arc gradient.
Get it?
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