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<blockquote data-quote="lodbrok" data-source="post: 21704590" data-attributes="member: 558599"><p><img src="/styles/default/xenforo/smilies/default/yes.gif" class="smilie" loading="lazy" alt=":yes:" title="Yes :yes:" data-shortname=":yes:" /> <img src="/styles/default/xenforo/smilies/default/yes.gif" class="smilie" loading="lazy" alt=":yes:" title="Yes :yes:" data-shortname=":yes:" /></p><p></p><p><img src="http://i.imgur.com/MfjJT6e.png" alt="" class="fr-fic fr-dii fr-draggable " style="" /></p><p></p><p>S represents the light source, while r represents the measured points. The lines represent the flux emanating from the source. The total number of flux lines depends on the strength of the source and is constant with increasing distance. A greater density of flux lines (lines per unit area) means a stronger field. The density of flux lines is inversely proportional to the square of the distance from the source because the surface area of a sphere increases with the square of the radius. Thus the strength of the field is inversely proportional to the square of the distance from the source.</p></blockquote><p></p>
[QUOTE="lodbrok, post: 21704590, member: 558599"] :yes: :yes: [IMG]http://i.imgur.com/MfjJT6e.png[/IMG] S represents the light source, while r represents the measured points. The lines represent the flux emanating from the source. The total number of flux lines depends on the strength of the source and is constant with increasing distance. A greater density of flux lines (lines per unit area) means a stronger field. The density of flux lines is inversely proportional to the square of the distance from the source because the surface area of a sphere increases with the square of the radius. Thus the strength of the field is inversely proportional to the square of the distance from the source. [/QUOTE]
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