Reply to thread

Message: <blockquote data-quote="imhotep" data-source="post: 23929185" data-attributes="member: 562115">There is really an another version of the needle problem....The "needle" can be extended to any convex polygon with a generalized diameter (this is the maximum distance between any two points on the boundary of a closed figure), less than the distance between the drawn lines (d)Then the probability P that the boundary of the polygon will intersect one of the lines is P = p/{(pi)*d} where p is the perimeter of the polygon.Also there's another variant named Buffon-Laplace Needle problem, where instead of the parallel lines, now you have two sets of perpendicular parallel lines forming a squared grid.The name Laplace is appended because Buffon made an error in deriving the Probability for this case, but later Laplace corrected it.</blockquote>

Top Bottom