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ElaKiri Talk!
1+1=1 Fully Proverd with Real Maths
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<blockquote data-quote="rajitha_ks" data-source="post: 7487484" data-attributes="member: 162025"><p>i don't know what this bing thing has to do with giving out seemingly false results.</p><p></p><p>but try the inverse of division (that is multiplication)</p><p></p><p>your argument is that any number divided by zero is infinity right?</p><p></p><p>lets take your any number as "5"</p><p></p><p>then 5/0 = "infinity"</p><p></p><p>so does it mean that 0* "infinity" = 5 ?</p><p></p><p></p><p>if you look at the previous operation closely, you'd notice that thre's a 0/0 instance involved in translating division to multiplication. this situation arose because we took 5/0 as a legitimate expression, which is not acceptable in math.</p><p></p><p>also the number zero does not have a multiplicative inverse in group theory</p><p>(division is defined as multiplication with multiplicative inverse.. like when you say you divide 10 by 2 what you actually are doing is that you are multiplying by the inverse of 2 {10/2 == 10 * (2)^-1 } so in order to be able to divide by zero, this number zero should have a multiplicative inverse..ie.. (0)^-1. now what's the value of that? is it infinity ? i think not.</p></blockquote><p></p>
[QUOTE="rajitha_ks, post: 7487484, member: 162025"] i don't know what this bing thing has to do with giving out seemingly false results. but try the inverse of division (that is multiplication) your argument is that any number divided by zero is infinity right? lets take your any number as "5" then 5/0 = "infinity" so does it mean that 0* "infinity" = 5 ? if you look at the previous operation closely, you'd notice that thre's a 0/0 instance involved in translating division to multiplication. this situation arose because we took 5/0 as a legitimate expression, which is not acceptable in math. also the number zero does not have a multiplicative inverse in group theory (division is defined as multiplication with multiplicative inverse.. like when you say you divide 10 by 2 what you actually are doing is that you are multiplying by the inverse of 2 {10/2 == 10 * (2)^-1 } so in order to be able to divide by zero, this number zero should have a multiplicative inverse..ie.. (0)^-1. now what's the value of that? is it infinity ? i think not. [/QUOTE]
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