A/L maths karana kenek help ekak denna plzzz

[princeofpersia2008]

නිශ්චලතාවයේ සිට ගුරුත්වය යටතේ නිදහසේ පහත වෑටෙන වස්තුවක් එය පහලට වෑටෙන අන්තිම තත්පරය තුල මුලු දුරින් 19% ගමන් කලේය.

1.වස්තුව පොලවට වෑටීමට ගතවන කාලය ?
2. වස්තුව පොලවට කොපමන උසකින් පිහිටියේද ?


mata me gana hadala hadana widiya kiyala denna puluwanda plzz loku udauwak

 

[lasankandy]

Danne na ban. mam commerce kare.

 

[princeofpersia2008]

Danne na ban. mam commerce kare.

aulak na machan

 

[lasankandy]

aulak na machan

 

[chethiyakb]

Machang,,,,

Total time = n kiyala ganin then
time until the last sec. = n-1 then assume that the total displacement = 100 m kiyala, then (n-1) sec.s waladi object eka 81m gihin kiyala hithapang...

then use the equations of motion to get the answer ( use S=ut +0.5at^2)

 

[princeofpersia2008]

Machang,,,,

Total time = n kiyala ganin then
time until the last sec. = n-1 then assume that the total displacement = 100 m kiyala, then (n-1) sec.s waladi object eka 81m gihin kiyala hithapang...

then use the equations of motion to get the answer ( use S=ut +0.5at^2)

machan 100m kiyala assume karoth t hariyata enne nane mama karala baluwa :S

 

[DJ__MAL]

Machang,,,,

Total time = n kiyala ganin then
time until the last sec. = n-1 then assume that the total displacement = 100 m kiyala, then (n-1) sec.s waladi object eka 81m gihin kiyala hithapang...

then use the equations of motion to get the answer ( use S=ut +0.5at^2)

U = 0 na atakota ana sameekaranaya wesada pan answer aka anawa

 

[Gehan_Digits]

S = Ut + 1/2at^2 daapan..

 

[dragonlord]

 

[MrShashika]

tot n unama .. tot diz- 100 m kiyala hithuwama . n-1---------->100*19/100 k wenawa .. ethakota wastuwa 100*19/100 m durak pahalata wetila thiyenawa .. s=ut+1/2at*2 danna dan .. s dannawa .. ut=0 unama .. time eka hoya ganna puluwan wei

 

[dilrasan]

meka godak sarthakayi...

 

[dragonlord]

ube method 1kth hari machn bt unknown godak wedi wage neda?