A simple work sharing puzzle

imhotep

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  • Mar 29, 2017
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    Lionel & Mary can finish painting a room in 2 hours.
    Lionel & Noel can finish the same painting job in 3 hours.
    Mary & Noel together is able to finish it in 4 hours.

    If all three of them work together how long the job will take? :rolleyes:
    (Assume that each person works at a constant rate whether working as an individual or with the team)
     

    imhotep

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  • Mar 29, 2017
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    The correct answer is 24/13 as mentioned by @MrFrog :yes:

    Just think along these lines....

    Lionel & Mary ---> in one hour ----> completes 1/2 the job
    Lionel & Noel ---> in one hour ----> completes 1/3 the job
    Mary & Noel ---> in one hour ----> completes 1/4 the job
     
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    aruna1

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  • Apr 22, 2008
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    The correct answer is 24/13 as mentioned by @MrFrog :yes:

    Just think along these lines....

    Lionel & Mary ---> in one hour ----> completes 1/2 the job
    Lionel & Noel ---> in one hour ----> completes 1/3 the job
    Mary & Noel ---> in one hour ----> completes 1/4 the job
    I disagree.
    Process is faster as the slowest sub process in a chain
     

    imhotep

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    I disagree.
    Process is faster as the slowest sub process in a chain
    OK... Lionel & Mary can finish the job in 2 hours. So obviously Lionel, Mary & Noel together has to finish the job less than 2 hours.
    24/13 is just less than 2 hours - it's about 1 hr 50 mins. :yes:
     
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    MrFrog

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  • Jun 25, 2018
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    මාතර
    The correct answer is 24/13 as mentioned by @MrFrog :yes:

    Just think along these lines....

    Lionel & Mary ---> in one hour ----> completes 1/2 the job
    Lionel & Noel ---> in one hour ----> completes 1/3 the job
    Mary & Noel ---> in one hour ----> completes 1/4 the job
    thanks for the simple but nice puzzle. I did this in the same manner, but using x,y,z for the names :lol: . without solving for x or y or z individually, just got the answer for 1 / (x+y+z).

    for the guys who didn't do this..
    x= no. of rooms Lionel completes in one hour,
    y = no. of rooms Mary completes in one hour
    z = no. of rooms Noel completes in one hour

    x + y = 1/2 ------ (1)
    x + z = 1/3 ------ (2)
    y + z = 1/4 ------ (3)

    (1) + (2) +(3)
    x + y + x + z + y + z = 1/2 + 1/3+ 1/4
    2 (x + y + z) = 13 / 12
    x + y + z = 13 / 24

    1 / (x + y + z) = 24 /13

    1/ (x+ y + z) This is the answer we need. You should be able to interpret this if you didn't skip the o/l maths lessons :lol:
     
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    aruna1

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  • Apr 22, 2008
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    OK... Lionel & Mary can finish the job in 2 hours. So obviously Lionel, Mary & Noel together has to finish the job less than 2 hours.
    24/13 is just less than 2 hours - it's about 1 hr 50 mins. :yes:
    Ya you are correct. I assumed that the section assigned for each person is always the same, which leads to 4 hours
     
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