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<blockquote data-quote="imhotep" data-source="post: 24516277" data-attributes="member: 562115"><p>The answer to your question in a mathematical way, you can use the Poiseuille’s equation.</p><p>vessel radius (r), vessel length (λ) and viscosity of blood (η)</p><p>Blood Flow = π * ΔP * r^^4 * 8* η * λ (Note π = pi)</p><p></p><p>Also Blood Flow = ΔP/Resistance</p><p>Then we have..</p><p>Resistance = 8ηλ/πr^^4</p><p></p><p>Suppose that he flow rate of an artery is reduced to half of it;'s normal value due to deposits narrowing it.. </p><p>You can easily calculate using the above equation...</p><p>the new radius = 0.841 *old radius (a decrease of nearly 16%)</p><p></p><p>Note - the decrease of 16% affects in a big way - flow rate is reduced to half!</p><p>Because of the r^^4</p></blockquote><p></p>
[QUOTE="imhotep, post: 24516277, member: 562115"] The answer to your question in a mathematical way, you can use the Poiseuille’s equation. vessel radius (r), vessel length (λ) and viscosity of blood (η) Blood Flow = π * ΔP * r^^4 * 8* η * λ (Note π = pi) Also Blood Flow = ΔP/Resistance Then we have.. Resistance = 8ηλ/πr^^4 Suppose that he flow rate of an artery is reduced to half of it;'s normal value due to deposits narrowing it.. You can easily calculate using the above equation... the new radius = 0.841 *old radius (a decrease of nearly 16%) Note - the decrease of 16% affects in a big way - flow rate is reduced to half! Because of the r^^4 [/QUOTE]
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