complex equation

hipa

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Feb 24, 2007
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you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.
 

nimaz

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Nov 4, 2006
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hipa said:
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.

hari!!
 

hipa

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Feb 24, 2007
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sorry new to elakiri did not know how look at old threads
avakalana koroth mokadawenne ? function ekaka avakalanaya karala 0 t set karama lebenne ekko (i) maximum wena point (ii) nettham minimum wena point (ii) netham "herenna gihilla ayeth kelin yana point" (y=x^3, x=0 de wage) misak function eka 0 wena point lebenne ne . eheinda eqution solve karanne giyama avakalaneya karanna epa
 

nabil

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Mar 4, 2007
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hipa said:
you can write the equation as (5^x)^2-(5^x)(5)+4=0
Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.
ahh yes yes. i was about to say that :D
 

hipa

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Feb 24, 2007
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who is the most romantic? math guy or medico
a math guy and a medico are walking along and see a very pretty girl coming.
medico saw the girl's lungs, kidney's, spinal cords etc. math guy saw the smooth surfaces, uparima laksha (maximum points), avama laksha (minimum points), smooth surfaces and other interesting points (avakalanya 0 wena sthana).
Who is the most romantic ?
 

sajithd

Well-known member
  • Aug 3, 2007
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    uNkOWn
    hipa said:
    you can write the equation as (5^x)^2-(5^x)(5)+4=0
    Now substitute t=5^x. Now we get t^2-5t+4=0. This is a simple quadratic in t and can be factored as (t-4)(t-1)=0. Which gives t=4 or t=1. Now put back 5^x=t. You get 5^x=4 or 5^x=1, which means x=log_5(4) or x=0. Hope this helps.


    thanx machan.