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Ganan Hadamuda?
- Thread starter පැටියා
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Menna answer eka :
fg(x)=f(x)g(x)
fg'(x)=f'(x)g(x)+g'(x)f(x)
fg''(x)={f''(x)g(x)+g'(x)f'(x)} + {g''(x)f(x)+f'(x)g'(x)}
fg''(x)=f''(x)g(x) + g''(x)f(x) + 2f'(x)g'(x)
x=a,
fg''(a)=f''(a)g(a) + g''(a)f(a) + 2f'(a)g'(a)
Try karala balanna thibunane.
meka easy.
fg(x)=f(x)g(x)
fg'(x)=f'(x)g(x)+g'(x)f(x)
fg''(x)={f''(x)g(x)+g'(x)f'(x)} + {g''(x)f(x)+f'(x)g'(x)}
fg''(x)=f''(x)g(x) + g''(x)f(x) + 2f'(x)g'(x)
x=a,
fg''(a)=f''(a)g(a) + g''(a)f(a) + 2f'(a)g'(a)
Try karala balanna thibunane.
meka easy.
Menna answer eka :
fg(x)=f(x)g(x)
fg'(x)=f'(x)g(x)+g'(x)f(x)
fg''(x)={f''(x)g(x)+g'(x)f'(x)} + {g''(x)f(x)+f'(x)g'(x)}
fg''(x)=f''(x)g(x) + g''(x)f(x) + 2f'(x)g'(x)
x=a,
fg''(a)=f''(a)g(a) + g''(a)f(a) + 2f'(a)g'(a)
Try karala balanna thibunane.
meka easy.
Elazzz
Thanks machan
පැටියා;7491904 said:na ban apita 2nd exaam
real analysis ha?
which university are you in? and which year? i might just be able to provide you with some help (with some past papers and all
)පැටියා;7491904 said:na ban apita 2nd exaam
hapoooo maaath asama naththe exam walata banz.... Exam nathi rataka ipaduna nam maruu
lol i just love exams. seriously
පැටියා;7491950 said:sirada?
ow machan.. for some reason exam tension cheers me up in some wired way.. i don't know why but i kinda like it
and as i said earlier, i might be able to help you with some past papers and all.. what's ur uni? which year?
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