Geometric Puzzle - 17_06_24

[imhotep]

Easy problem. Can be solved in several ways.




Given :
The radius of the semicircle is 5 units.
Angle ACE = Angle BCD = 60 degrees

Find: The length DE

 

[Tricle_Buwa]

Bump

 

[topkollek]

C can be placed anywhere on AB to satisfy given conditions

 

[imhotep]

C can be placed anywhere on AB to satisfy given conditions

Good observation.

 

[dilann]

5 (cos60) x 2

Ehema oneth na.. niknma 5 enwa samapada thrikona awsthawa gaththma

 

[54H4N]

C can be placed anywhere on AB to satisfy given conditions

එහෙනම් C කේන්ද්‍රයට දැම්මම,
EDC සමපාද ත්‍රිකෝණයක්

DE = 5

 

[imhotep]

එහෙනම් C කේන්ද්‍රයට දැම්මම,
EDC සමපාද ත්‍රිකෝණයක්
View attachment 231546
DE = 5

Yes... That's exactly what I meant by "Good observation" comment above.

 

[dilann]

If these are five squares, find a

 

[imhotep]

If these are five squares, find a

Though it appears to be a bit odd there's a solution. I won't mention the answer but,

Tip: Mark the sides of the small square as 1 cm, then say the top left square has a side length of "x", proceed to get the sides of the other squares.

 

[54H4N]

If these are five squares, find a

a = 4

 

[Stimulus mind]