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<blockquote data-quote="ahamednishadh" data-source="post: 2606622" data-attributes="member: 4368"><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">k found da answer</span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">lets say thus</span></strong></p><p><strong><span style="font-size: 18px">triangle=T , circle=C & square=S</span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">so according to da 1st balance</span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"><span style="color: Blue">T+2S=3C</span></p><p></span></strong></p><p><strong><span style="font-size: 18px">according to da 2nd balance</span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"><span style="color: Blue">T+C=6S</span></p><p></span></strong></p><p><strong><span style="font-size: 18px">according to da 3rd balance</span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"><span style="color: Blue">2S+C=?</span></p><p></span></strong></p><p><strong><span style="font-size: 18px">therefore da first two equatins above can also be writen thus:</span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"><span style="color: Blue">3C-2S=T</span> --- <span style="color: Red">(Eq 1)</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"><span style="color: Blue">6S-C=T </span> --- <span style="color: Red">(Eq 2)</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"></p><p></span></strong></p><p><strong><span style="font-size: 18px">therefore subtracting Eq 2 from Eq 1 can be shown thus</span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px">1. <span style="color: Blue">3C - 2S - (6S - C) = T - T</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px">2. <span style="color: Blue">3C - 2S - 6S + C = 0</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px">3. <span style="color: Blue">4C - 8S = 0</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px">4. therefore <span style="color: Blue">4C = 8S</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px">5. therefore <span style="color: Blue">C = 2S</span></p></span></strong></p><p style="margin-left: 20px"><strong><span style="font-size: 18px"></p><p></span></strong></p><p><strong><span style="font-size: 18px">so we now know that 1 Circle is equal to 2 Squares.</span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">therefore in da first scale we c <span style="color: Blue">1 Triangle + 2 Squares = 3 Cirlces</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">so if 1 Circle and 2 Squares are taken off from the first scale it will still balance which means that <span style="color: Blue">1 Triangle = 2 Circles</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">so in da 3rd scale we c <span style="color: Blue">1 Cirlce and 2 Squares</span> which is also equal to <span style="color: Blue">2 Circles</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">so as we have found out dat <span style="color: Blue">2 Circles = 1 Triangle</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px">then <span style="color: Blue">1 Circle + 2 Squares = 1Triangle</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p><p><strong><span style="font-size: 18px"><span style="color: Yellow">Bro answer eka hari neda???????????</span></span></strong></p><p><strong><span style="font-size: 18px"></span></strong></p></blockquote><p></p>
[QUOTE="ahamednishadh, post: 2606622, member: 4368"] [B][SIZE="5"] k found da answer lets say thus triangle=T , circle=C & square=S so according to da 1st balance [INDENT][COLOR="Blue"]T+2S=3C[/COLOR][/INDENT] according to da 2nd balance [INDENT][COLOR="Blue"]T+C=6S[/COLOR][/INDENT] according to da 3rd balance [INDENT][COLOR="Blue"]2S+C=?[/COLOR][/INDENT] therefore da first two equatins above can also be writen thus: [INDENT][COLOR="Blue"]3C-2S=T[/COLOR] --- [COLOR="Red"](Eq 1)[/COLOR] [COLOR="Blue"]6S-C=T [/COLOR] --- [COLOR="Red"](Eq 2)[/COLOR] [/INDENT] therefore subtracting Eq 2 from Eq 1 can be shown thus [INDENT]1. [COLOR="Blue"]3C - 2S - (6S - C) = T - T[/COLOR] 2. [COLOR="Blue"]3C - 2S - 6S + C = 0[/COLOR] 3. [COLOR="Blue"]4C - 8S = 0[/COLOR] 4. therefore [COLOR="Blue"]4C = 8S[/COLOR] 5. therefore [COLOR="Blue"]C = 2S[/COLOR] [/INDENT] so we now know that 1 Circle is equal to 2 Squares. therefore in da first scale we c [COLOR="Blue"]1 Triangle + 2 Squares = 3 Cirlces[/COLOR] so if 1 Circle and 2 Squares are taken off from the first scale it will still balance which means that [COLOR="Blue"]1 Triangle = 2 Circles[/COLOR] so in da 3rd scale we c [COLOR="Blue"]1 Cirlce and 2 Squares[/COLOR] which is also equal to [COLOR="Blue"]2 Circles[/COLOR] so as we have found out dat [COLOR="Blue"]2 Circles = 1 Triangle[/COLOR] then [COLOR="Blue"]1 Circle + 2 Squares = 1Triangle[/COLOR] [COLOR="Yellow"]Bro answer eka hari neda???????????[/COLOR] [/SIZE][/B] [/QUOTE]
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