No not this but the very 1st prob given >>>> it leads to contradictionindikson said:Secx=1/cos x
Cosecx= 1/sinx
Secx.Cosecx=1/cosx sinx
this method is correct
May be this is a late reply,VSGM said:![]()
is the question correct, pls show me the method to do this!!
VSGM said:![]()
is the question correct, pls show me the method to do this!!
How can you get 2 equilateral triangles. Then each angle is 60 degrees. That will be a very special case. Here it is clearly marked the angles are different in value.dammamuditha said:if s is a point in QR then we will have 2 equilateral triangles, PQR and PRS.
Then we can write PR/SR = QR/PR
then PR^2 = RS.QR
wicky_ts said:How can you get 2 equilateral triangles. Then each angle is 60 degrees. That will be a very special case. Here it is clearly marked the angles are different in value.
are u doing A/L?wicky_ts said:How can you get 2 equilateral triangles. Then each angle is 60 degrees. That will be a very special case. Here it is clearly marked the angles are different in value.
djHiran said:Challange: define the null graph using set theory!
According to definition of a graph G = (V,E) where V is the set of vertices and E is the set of edges.
Considering the uniqueness of null element can you define the null graph?