maths help (me HU**A kiyala dendoooo)

[zed]

meke slove koranne kohomedooooo?

 

[zed]

 

[nagaya]

meke slove koranne kohomedooooo?

intrigrate it by x
then dy/dx=0
then u'll get stationary points

 

[nagaya]

do same and you can get maxima & minima.....check wheather it's maxima or minima

 

[zed]

intrigrate it by x
then dy/dx=0
then u'll get stationary points

bit specific pleese

onne intigrate kolame


y = 2x + 6/x
y = 2x + 6x^-1

dy/dx = 2 - 6x^-2

slove koraddi

0=2-6x^-2
-2=-6/x^2

minus welete minuse nathi wenewa

2 = 6/x^2

haras gunithaya

6/2 = x^2

then the answer is 

+or- Sq root 3

thx eranga_m 4 the online hlp:D:rofl:

dan oke apply korenewa 1st eq 1kte

 

[nagaya]

yeah then u'll get stationary points...then check max or min...
ai ban umbala owa karalama nadda?umba AL neda?AL walata owa ugannawane

bit specific pleese

onne intigrate kolame


y = 2x + 6/x
y = 2x + 6x^-1

dy/dx = 2 - 6x^-2

slove koraddi

0=2-6x^-2
-2=-6/x^2

minus welete minuse nathi wenewa

2 = 6/x^2

haras gunithaya

6/2 = x^2

then the answer is 

+or- Sq root 3

thx eranga_m 4 the online hlp:D:rofl:

dan oke apply korenewa 1st eq 1kte

 

[zed]

yeah then u'll get stationary points...then check max or min...
ai ban umbala owa karalama nadda?umba AL neda?AL walata owa ugannawane

AL neme ban


dan kohomede ban max the min the kiyela hoyanne

kiyela diyanneko
mate melo magulak therenne na

 

[zed]

nagaya skype/yahoo/msn/digsby/facebook wele eheme naddo?

(dale galwela nede thiyenne? )

 

[nagaya]

AL neme ban


dan kohomede ban max the min the kiyela hoyanne

kiyela diyanneko
mate melo magulak therenne na

dan mehemai
point eka x=3 kiyala awnam
ita poddak adu ekak like 2.9 wage dy/dx ta aadesha kaloth enne + ekak
& wadi ekak like 3.1 aadesha kalama enne - ekak nam eka max ekak ne
anik paththata awoth min ekak...

dan stationary point godai nam aadesha karanna one ewa athara ekak..nathnm wena ekaka function eke hasireema ennne....

umba owa monatada balanne ?

meka balapn

http://mathworld.wolfram.com/StationaryPoint.html
http://library.thinkquest.org/C0110248/calculus/cartestat.htm
http://www.tlchm.bris.ac.uk/~paulmay/misc/1s/calclt5.htm

hope these will help u

 

[zed]

dan mehemai
point eka x=3 kiyala awnam
ita poddak adu ekak like 2.9 wage dy/dx ta aadesha kaloth enne + ekak
& wadi ekak like 3.1 aadesha kalama enne - ekak nam eka max ekak ne
anik paththata awoth min ekak...

dan stationary point godai nam aadesha karanna one ewa athara ekak..nathnm wena ekaka function eke hasireema ennne....

umba owa monatada balanne ?

meka balapn

http://mathworld.wolfram.com/StationaryPoint.html
http://library.thinkquest.org/C0110248/calculus/cartestat.htm
http://www.tlchm.bris.ac.uk/~paulmay/misc/1s/calclt5.htm

hope these will help u

me gane compleete specific solution 1kk denne puluwando

 

[nimaz]

meke slove koranne kohomedooooo?

Theory:

For a function: y = f(x), a stationary point is a point on the function graph where the gradient of the function is zero.

If the gradient of the function changes sign at the stationary point, then it is called a turning point, which can be a maximum or minimum


If f''(x) < 0, the stationary point at x is a maxima
If f''(x) > 0, the stationary point at x is a minima
If f''(x) = 0, the stationary point at x is a point of inflexion

-------------------------------------------------------------------------------------------------------------------

this is the answer!

Y= 2X + (6/X)
Y= 2X + 6X^(-1)
dy/dx = 2 - 6X^(-2) (to find the stationary point)
therefore

0= 2 - 6X^(-2)
OR
0= 2 - 6/(X^2)
6/(X^2) = 2
6 = 2(X^2)
3= (X^2)
X = (+ OR - ) (SQUARE ROOT OF 3)
SUB X = (+ OR - ) (SQUARE ROOT OF 3) IN Y= 2X + (6/X)
TO GET THE Y VALUES

THE NATURE OF EACH POINT...
X = + SQUARE ROOT OF 3
Y =......
IS A MINIMA

X = - SQUARE ROOT OF 3
Y = ......
IS A MAXIMA

GOOD LUCK

 

[nimaz]

http://mathworld.wolfram.com/StationaryPoint.html

 

[nagaya]

me gane compleete specific solution 1kk denne puluwando

dan mehemai machan
stationary points +mula3 and -mula3 ne
dan mehema gamu

from -infinty to -mula3 dy/dx > 0
on -mula 3 dy/dx=0
from -mula3 to +mula3 dy/dx < 0
on +mula 3 dy/dx=0
from +mula3 to +infinty dy/dx > 0

so at -mula3 it's max ; at +mula 3 it's min

 

[g1tha741741]

matanam melo magulak therene ne owa grade kiye ewada???

 

[nagaya]

matanam melo magulak therene ne owa grade kiye ewada???

ane podi babooo ;owa grade 12 ewane

 

[g1tha741741]

ane podi babooo ;owa grade 12 ewane

ahh ehemada grade 10 ewa theyenan ahanda mama kiyala denam

 

[zed]

2nd derivetive 1k ganne kohomedooooooooo

0=12x^-3
0=x^-3
0=1/x^3


kohomede othening next step 1k te yanne

 

[rudayas]

EK Further Maths class ah?
ela ela ohoma yang
kattiyatama wisadaganna beri ganak tibboth mata kiyannakooo

 

[nagaya]

2nd derivetive 1k ganne kohomedooooooooo

0=12x^-3
0=x^-3
0=1/x^3


kohomede othening next step 1k te yanne

machan function eka diyanko man kiyanna karana hati

 

[dimaroxx]

sry dont no looolzzz