maths help

[zed]

 

[zed]

part b dannewa

part A kiyala deehalla

 

[coolshano]

wooooooooow

 

[madurax86]

dv/dt = 6t+1

{ dv ={ (6t+1) dt        integrate both LHS and RHS,   * { is used for integration symbol

v=3t^2 + t + c

dx/dt=3t^2 + t + c                 c: integral constant

{ dx= { ( 3t^2+t+c ) dt

x=t^3+0.5*t^2 +ct + d          d: another integral constant

substitution 
x=12,t=2
12=8+2+2c+d  => 2=2c+d ------------(1)

x=34,t=3
34=27+4.5+3c+d   =>  2.5=3c +d ---(2)

(2)-(1)
0.5=c
substituting to (1); d=1

x=t^3+0.5*t^2+0.5t+1
t=4;
x=64+8+2+1=75m

v=3t^2 + t + c 
t=4;
v=3*16+4+0.5= 52.5 ms^-1

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