Maths Issue

Anti BBS

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Feb 7, 2015
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machans any body can solve this.?

nxlx6u.jpg
 

ruchira55

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  • Mar 23, 2012
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    7x=(a+2b+3c)
    x=(a+2b+3c)/7

    (x − a)2 + (2x − b)2 + (3x − c)2 kiyana ekata x walata apu, (a+2b+3c)/7 apply karanna
    ethakota ei,
    [(a+2b+3c)/7 − a]2 + {[2(a+2b+3c)/7] − b}2 + {[3(a+2b+3c)/7] − c}2

    dan, a+2b+3c)/7 kiyana ekata 7x apply karanna

    ethakota [(7x/7) − a]2 + [2(7x/7) − b]2 + [3(7x/7) − c]2
    hathata hatha kapapan

    ethakota ei ara uttare

    PS: goda kalekin ban mewa gana hithuwe. waradidia danne naha
     
    Last edited:

    Anti BBS

    Member
    Feb 7, 2015
    4,160
    674
    0
    Amsterdam
    7x=(a+2b+3c)
    x=(a+2b+3c)/7

    (x − a)2 + (2x − b)2 + (3x − c)2 kiyana ekata x walata apu, (a+2b+3c)/7 apply karanna
    ethakota ei,
    [(a+2b+3c)/7 − a]2 + {[2(a+2b+3c)/7] − b}2 + {[3(a+2b+3c)/7] − c}2

    dan, a+2b+3c)/7 kiyana ekata 7x apply karanna

    ethakota [(7x/7) − a]2 + [2(7x/7) − b]2 + [3(7x/7) − c]2
    hathata hatha kapapan

    ethakota ei ara uttare

    PS: goda kalekin ban mewa gana hithuwe. waradidia danne naha


    (x − a)2 + (2x − b)2 + (3x − c)2 − (a2 + b2 + c2).
    (1 + 4 + 9)x2 − 2x(a + 2b + 3c)

    a + 2b + 3c = 7x

    (22 + 32 + 32)x2 − 2x(2a + 3b + 3c)
    2a + 3b + 3c = 11x.