මුලින් ම අලුත් ප්රොජෙක්ට් එකක් Open කරන්න Console mode එක තෝරගන්න
ඊට පස්සෙ ඔය code එක paste කරන්න(මුලින් එතන තියෙන කෝඩ් එක අයින් කරන්න)
ඊට පස්සෙ F9 ගහන්න.
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Thread for Programming and Realeted Topics
- Thread starter rclakmal
- Start date
මුලින් ම අලුත් ප්රොජෙක්ට් එකක් Open කරන්න Console mode එක තෝරගන්න
ඊට පස්සෙ ඔය code එක paste කරන්න(මුලින් එතන තියෙන කෝඩ් එක අයින් කරන්න)
ඊට පස්සෙ F9 ගහන්න.
Hey no one seem to be interested in programming stuff !!!!!! Please post ur problems here .........i mean then we can develop solutions using a language we know !!!!! Its really fun guys !!!!!! cmon !!!!!!!
i saw a question on "YAHOO ANSWERS" and and here is my solution for all of u !!!!!!
Question was ---
and here is my answer
Happy coding !!!!!
[/SIZE]
Question was ---
Code:
[B][SIZE=2]How to do this java programme?[/SIZE][/B]
[SIZE=2]Q3. Write a program to draw a diamond sign in to the screen with different heights entered by the user. See following example.
Enter the height of the diagonal: 7
*
* *
* * *
* * * *
* * *
* *
*
[URL]http://answers.yahoo.com/question/index?qid=20090925215708AAkjRKl[/URL]and here is my answer
Code:
package diamond;
import java.util.Scanner;
/**
*
* @author lakmal
*/
class Diamond {
/**
* @param args the command line arguments
*/
static int height;
static char state;
Diamond(int height){
for (int i=1;i<=height;i++){
if (i<=(height/2)){
for (int j=1;j<=i;j++){
System.out.print(" *");
}
}
else{
for(int j=1;j<=(height+1-i);j++){
System.out.print(" *");
}
}
System.out.println();
}
}
public static void main(String[] args) {
// TODO code application logic here
Scanner input=new Scanner(System.in);
do{
do{
System.out.println("Enter your height");
height=input.nextInt();
Diamond d1=new Diamond(height);
} while(height%2!=0);
System.out.println("Enter a odd number!!");
System.out.println("Do you want to continue?(y/n)");
state=input.next().charAt(0);
} while(state=='y');
}
}Happy coding !!!!!
[/SIZE]
ඔහොම කරන්න බෑ නේ...
In the Console you cant output text like dialog boxes
they are fixed-width if you want a diamond shape you should try either a text box or if you want to use the console
you should use
Code:
*
***
*****
***
*it should be 1,3,5,7,5,3,1 -- that would be the only output that prints a proper diamond in console
Last edited:
Onna apith awa ehenam
ප්රශ්න ඉදිරිපත් කරන්න
නැත්නම් ඔයා හොයාගත්ත algorithms, routines මේකෙ පෝස්ට් කරන්න(හොයාගත්ත කියන්නෙ කලින් අහලවත් නැති වෙන්න ඕන නෑ ඔයා අලුත් ක්රමයක් හොයාගත්තා නම් ඒක දාන්න)
Onna apith awa ehenam
elaz macho !!!!! digatama touch eke idapan !!!!
Machan MADHURA i think u were right in the above matter .First of all i should say that the above code doesn't provide a diamond .Actually in that "yahoo answer " problem ,i saw the output as a a triangle ......and i didnt read the whole question .....(may be an error in loading the web page) then i started coding as an idiot
and finally copy pasted the question and my answer here..........but only after reading this thread again i saw it was asked to design a DIAMOND output .
.........and then i tried to achieve that particular output,diamond.!!!! as u have mentioned i couldn't get the real shape !!! The reason should be that .Thanks for your contribution. here is the updated code
Code:
package diamond;
import java.util.Scanner;
/**
*
* @author lakmal
*/
class Diamond {
/**
* @param args the command line arguments
*/
static int height;
static char state;
Diamond(int height){
for (int i=1;i<=height;i++){
if (i<=(height+1)/2){
for (int j=1;j<=i;j++){
for (int k=1;k<=((height+1)/2)-i;k++){
System.out.print(" ");
}
System.out.print(" *");
}
}
else {
for(int j=1;j<=(height+1-i);j++){
for (int k=1;k<=i-((height+1)/2);k++){
System.out.print(" ");
}
System.out.print(" *");
}
}
System.out.println();
}
}
public static void main(String[] args) {
// TODO code application logic here
Scanner input=new Scanner(System.in);
do{
do{
System.out.println("Enter your height");
height=input.nextInt();
Diamond d1=new Diamond(height);
} while(height%2!=0);
System.out.println("Enter a odd number!!");
System.out.println("Do you want to continue?(y/n)");
state=input.next().charAt(0);
} while(state=='y');
}
}
Last edited:
ප්රශ්න ඉදිරිපත් කරන්න
නැත්නම් ඔයා හොයාගත්ත algorithms, routines මේකෙ පෝස්ට් කරන්න(හොයාගත්ත කියන්නෙ කලින් අහලවත් නැති වෙන්න ඕන නෑ ඔයා අලුත් ක්රමයක් හොයාගත්තා නම් ඒක දාන්න)
denata nam prashna ne. Balamuko issarahata
The code that draws a diamond [c++]
this code only draws a proper diamond for odd integers
Screenshot
hey lakmal, use the gotoxy function for java it saves alot of time when things associated with drawing
this code only draws a proper diamond for odd integers
Screenshot
Code:
#include <cstdlib>
#include <iostream>
#include <windows.h>
using namespace std;
void gotoxy(int x, int y)
{
COORD coord;
coord.X = x;
coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}
main(int argc, char *argv[])
{
int i,j,k,l;
cin>>k;
for (i=0;i<=k;i++)
{
for (j=abs((k+1)/2-i)+1;j<=k-abs((k+1)/2-i);j++)
{
gotoxy(j,i+2);
cout<<"*";
}
}
cout<<endl;
system("PAUSE");
}
Last edited:
Machan can u please explain a bit about that function ...from line to line ....what each line does ......little bit confused about that !!!!! thanks !!!!!
Code:
#include <cstdlib>
#include <iostream>
#include <windows.h> //windows header file, we will be using some functions from this
using namespace std;
void gotoxy(int x, int y) //a function i took from the internet that will set the cursor at a given point in the console
{
COORD coord; // COORD is a C,C++ type for 2D points
coord.X = x;
coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord); //this line uses the functions from windows.h (header file) to set the cursor where we need
}
main(int argc, char *argv[]) // the main routine that is called when the program is started, the arguments are optional
{
int i,j,k,l;
cin>>k; //read the number of lines that we need to draw a diamond
for (i=0;i<=k;i++) //count from 0 to k
{
for (j=abs((k+1)/2-i)+1;j<=k-abs((k+1)/2-i);j++) //i adjusted this after some serious testing, I'll explain it below it takes alot of space
{
gotoxy(j,i+2); //goto the point j,i+10 in console
cout<<"*"; // write a "*" at that point
}
}
cout<<endl;
system("PAUSE"); //gives 'press any key to continue'
}When it counts form 0 to k that changes the y coordinate of the point where we are going to print the *
because the for loops are nested
for example
Code:
for (x=0;x<10;x++){
for (y=0;y<10;y++){
gotoxy(x,y);
cout<<"*";
}
}so we have configured what we want to do with the y coordinate it just keeps going down ..but the x coordinate is not like that it should goto where it prints the top * first then in the next line it should go where the second line's first star prints and should print 2 stars instead of one
abs(q) gives the absolute value of q, |q|
i have used it to get a series of numbers going up once and then coming down after a number for example
the graph, y=abs(10-x) or y=|10-x| is like that draw it and see if you want.
i used that to draw the diamond it sounds complex but actually i didnt go thru much complex stuff i just got the pattern and adjusted it!..
keep in mind that I did NOT write that code on my 1st try it was after a lot of compilations that I got the code working the way I want
Last edited:
Hey Guys check out this code !!!! get two points and return the line !! checked for all occurrences !!!! Please tell me if there are any errors !!!!!!
Happy Codings !!!!! For More Java And C++ codes Visit
http://www.elakiri.com/forum/showthread.php?t=245895
Code:
package line;
import java.util.Scanner;
/**
*
* @author lakmal
*/
class Line {
Points p1=new Points();
Points p2=new Points();
static boolean isContinue=true;
static Scanner input=new Scanner(System.in);
static String op;
void getLine(Points p1,Points p2){
System.out.println("Your two points are ");
System.out.println("("+p1.xCordinate+","+p1.yCordinate+")");
System.out.println("("+p2.xCordinate+","+p2.yCordinate+")");
double yCoeff=p2.xCordinate-p1.xCordinate;
double xCoeff=p2.yCordinate-p1.yCordinate;
double constant=p1.yCordinate*(p2.xCordinate-p1.xCordinate)-p1.xCordinate*(p2.yCordinate-p1.yCordinate);
System.out.println("Your Line is:");
if (yCoeff==0){
System.out.println("X="+p2.xCordinate);
}
else if (xCoeff==0)
System.out.println("Y="+p2.yCordinate);
else{
if (constant!=0){
if ((constant/yCoeff)>0){
op = "+";
}
else if ((constant/yCoeff)<0){
op="";
}
System.out.println("Y="+xCoeff/yCoeff+"X" + op + (constant)/yCoeff);
}
else
System.out.println("Y="+ xCoeff/yCoeff+"X");
}
}
void getPoints(){
System.out.println("Enter your First Point:");
System.out.print("X=");
this.p1.xCordinate=input.nextInt();
System.out.print("Y=");
this.p1.yCordinate=input.nextInt();
System.out.println("Enter your Second Point:");
System.out.print("X=");
this.p2.xCordinate=input.nextInt();
System.out.print("Y=");
this.p2.yCordinate=input.nextInt();
this.getLine(this.p1,this.p2);
}
public static void main(String[] args) {
do {
Line l1=new Line();
l1.getPoints();
System.out.println("Do you want to Continuw with anothe line:(y/n)");
char state=input.next().charAt(0);
if (state=='n')
isContinue=false;
} while (isContinue=true);
}
}
class Points {
int xCordinate;
int yCordinate;
}Happy Codings !!!!! For More Java And C++ codes Visit
http://www.elakiri.com/forum/showthread.php?t=245895
Hey guys Dont u have some kind of interest in programming ?????!! !!!!!!!! please join here and make comments on posted codes !!!!!!!!!!
So give something to develop us too
Hey did u try the above programmes with a language u know ........if u r also using java then make some improvements on the code and post here !!! Ill post more problems later !!!!!!!
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