bit specific pleese
onne intigrate kolame
y = 2x + 6/x
y = 2x + 6x^-1
dy/dx = 2 - 6x^-2
slove koraddi
0=2-6x^-2
-2=-6/x^2
minus welete minuse nathi wenewa
2 = 6/x^2
haras gunithaya
6/2 = x^2
then the answer is
+or- Sq root 3
thx eranga_m 4 the online hlp:D:rofl:
dan oke apply...