It's similar....
i = dq/dt - Current is the rate of flow of electric charge with respect to to time.
I think what you refer to as ප්ලාවිත ප්රවේගය is the drift velocity of the electrons. It was first explained the so called Drude Model in 1900, which is not perfect but good enough. Later on the Quantum scientists modified it and the Drude-Sommerfeld model was formed.
The drift velocity of electrons can be calculated by using the equation v = mσΔV/ρefℓ
where v is the drift velocity (m/sec)
m is the molecular mass of the metal (kg)
σ is the electric conductivity of the conductor (S/m)
ΔV is the voltage applied across the conductor (V)
ρ is the density (mass per unit volume) of the conductor (kg⋅m^−3)
e is the elementary charge, (C)
f is the number of free electrons per atom
ℓ is the length of the conductor (m)
Remember that the current is the total amount of charge passing through a particular point per second.
With the drift velocity v, in one second the charge carriers travel a distance of v
With a conductor of cross sectional area of A, a volume A x v of charge carriers passes a given point each second.
In the conductor, not all the charged particles are free to move, the carrier density n is the number of charge carriers free to move per cubic meter.
Thus the number of charge carriers passing a given point each second is therefore nAv
If each charge carriers have a charge of q, t the total charge passing each second is nAvq and this IS the current flow.
Thus i = nAvq This is also called the transport equation - and this is what the relationship is with the current and the drift velocity.
eg: Let's think we have a copper wire with a cross section of 0.5 mm2 (= 0.5 * 10^-6 m2) carrying a current of 5 Amps.
For copper we know that n = 8.5 × 10^28 per m3
The charge on an electron, q = 1.6 × 10^-19 C
So i = nAvq becomes 5 = 8.5 × 10^28 × 0.5 × 10^-6 × v × 1.6 × 10^-19
Hence, the Drift velocity v = 7.35 × 10^-4 m/sec (rather very slow)
Note: This is what the classical physics tells us. But there are other factors that involve Quantum mechanics, the Fermi velocity and skin effects that has to be taken into consideration. These are beyond discussion. But the above is a close approximation.
Thanks for your long reply machan and I already know most of it. But it still doesn't explain my problem.
" 1kV වල 50A යවන කොටයි 100kV වල 50A යවන කොටයි චලනය වෙන ඉලෙක්ට්රෝන වල හැසිරීමේ වෙනස මොකක්ද? "