A/L PHYSICS අමාරුද ?

[sandun36]

1: mcq thinking method
KE new = (1/2)mv^(2) *3

in here "m" is constant & "1/2" also constant . since v^(2) increases from thrice.
Hence v increases from 3^(1/2). which is the same with mv!
ans : 73% ( i.e.: because answer has asked just the increasing percentage of the mv!

2: more descriptive method

(1/2)mV^(2) = 3*(1/2)mv^(2) (in here v is prior velocity V is after velocity)
Result is V = 3^(1/2) v

now u wanna to know the increasing proportion of the mv with respect to old value:

(mV-mv)/mv = (3^(1/2)-1)v/v = 73%


If the answer require to have what is the new value w.r.t. to old it is 173%




al ekek hinda damme kolla! mamanam sallivalata class karanne na, a vunata ape moratuwe duppath evunta eva meva loku talk denna epa bun amruve jeevath vena evun innavane!

meke ta labena reply eka anuva thama deveni eka hadanavada nedda depend wenne!

 

[Ed.Win]

al ekek hinda damme kolla! mamanam sallivalata class karanne na, a vunata ape moratuwe duppath evunta eva meva loku talk denna epa bun amruve jeevath vena evun innavane!

man beluve me thread eka daapu ekkena eththada kiyanne kiyala.nethuva morotuwe inna duppath ayyalaata apahasa karanna nevei.anith eka ugannanava kiyana eka aavata giyata karanna be.gaana deepu gaman miniha athurudahan

 

[sandun36]

man beluve me thread eka daapu ekkena eththada kiyanne kiyala.nethuva morotuwe inna duppath ayyalaata apahasa karanna nevei.anith eka ugannanava kiyana eka aavata giyata karanna be.gaana deepu gaman miniha athurudahan

poddak balapan kollo okage panthi yanavanam oka just moratuweda danna, faculty ye nathuwa!

 

[Ed.Win]

poddak balapan kollo okage pathi yanavanam oka just moratuweda danna, faculty ye nathuwa!

moratuwa university kiyala daala thiyenne canteen ekeda danne ne

 

[Ed.Win]

1)
මෙතනදි ස්කන්ධයෙ වෙනසක් නෑ කියලා උපකල්පනය කරොත්

ශක්තිය සමානුපාතික වෙන්නෙ ප්‍රවේගයේ වර්ගයට
ගම්‍‍යතාව සමානුපාතික වෙන්නෙ ප්‍රවේගයට
ශක්තිය තුන් ගුණයකින් (300%) වැඩි උනා නම් ගම්‍යතාව උඩ යන්න ඕනේ මූල තුන කින්( 1.73)

1: mcq thinking method
KE new = (1/2)mv^(2) *3

in here "m" is constant & "1/2" also constant . since v^(2) increases from thrice.
Hence v increases from 3^(1/2). which is the same with mv!
ans : 73% ( i.e.: because answer has asked just the increasing percentage of the mv!

2: more descriptive method

(1/2)mV^(2) = 3*(1/2)mv^(2) (in here v is prior velocity V is after velocity)
Result is V = 3^(1/2) v

now u wanna to know the increasing proportion of the mv with respect to old value:

(mV-mv)/mv = (3^(1/2)-1)v/v = 73%


If the answer require to have what is the new value w.r.t. to old it is 173%

meke 300% kin chaalaka shakthiya ihala nanvana nisa avasana agayei,aarambaka agayei antharaya mul agayata darana anupaathaye 100ta agaya neveida ganna one

 

[sandun36]

වස්තුවක චාලක ශක්තිය 300%කින් ඉහළ නංවයි.එම වස්තුවේ ගම්‍යතාවය වැඩිවෙන ප්‍රතිශතය.මේ ගාන හදල පෙන්නපන්.ලේසි ගානක්

malli ahala thiyena prashneta uththara denna purudu weyan vishshenma mcq s waladi!


චාලක ශක්තිතිය 3 ගුනයකින් ඉහල යෑවුවයි කියන එක තෙරෙනවනෙ ! ග්මයතාවය අහල තියෙන්නෙ කිගුනයකින් ඉහල යනවද කියල නෙවෙ ! වෑඩි වෙන ප‍්රතිශතය !

believe u got the thing ! if not let me know!

 

[Ed.Win]

වස්තුවක චාලක ශක්තිය 300%කින් ඉහළ නංවයි.එම වස්තුවේ ගම්‍යතාවය වැඩිවෙන ප්‍රතිශතය.මේ ගාන හදල පෙන්නපන්.ලේසි ගානක්

malli ahala thiyena prashneta uththara denna purudu weyan vishshenma mcq s waladi!


චාලක ශක්තිතිය 3 ගුනයකින් ඉහල යෑවුවයි කියන එක තෙරෙනවනෙ ! ග්මයතාවය අහල තියෙන්නෙ කිගුනයකින් ඉහල යනවද කියල නෙවෙ ! වෑඩි වෙන ප‍්රතිශතය !

believe u got the thing ! if not let me know!

skandaya(m) niyathai

aarambaka chaalaka shakthiya = 1/2mx^2

avasaana chaalaka shakthiya = 1/2my^2

chaalaka shakthiya 300% vedi vuna nisa;

[(1/2my^2 - 1/2mx^2)/(1/2mx^2)]*100% = 300%

me tika sulu karahama,

(y^2 - x^2)/x^2 = 3


(y^2)/x^2 - 1 = 3


y/x = 2 -----------1


ema nisa gamyatha vedi veeme prathishathaya = [(my - mx)/mx]*100%

= (y/x - 1)*100%

1 vana sameekaranayen,

(y/x -1)*100% = (2-1)*100% = 100%


meka poddak balala,veradda kiyala denna

 

[chk99]

dan methana wenama tution ekak yanawa wage

 

[Ed.Win]

dan methana wenama tution ekak yanawa wage

 

[sandun36]

skandaya(m) niyathai

aarambaka chaalaka shakthiya = 1/2mx^2

avasaana chaalaka shakthiya = 1/2my^2

chaalaka shakthiya 300% vedi vuna nisa; =(1)

[(1/2my^2 - 1/2mx^2)/(1/2mx^2)]*100% = 300% = (2)

me tika sulu karahama,

(y^2 - x^2)/x^2 = 3


(y^2)/x^2 - 1 = 3


y/x = 2 -----------1


ema nisa gamyatha vedi veeme prathishathaya = [(my - mx)/mx]*100%

= (y/x - 1)*100%

1 vana sameekaranayen,

(y/x -1)*100% = (2-1)*100% = 100%


meka poddak balala,veradda kiyala denna

malli methana understanding wala prshnayak thiyenava machan! chalaka shakthiya 300% wenakan wedi wenne! nathnam 400% wenakan newe! (300% kiyanakotama othana hagenne thun gunayak wenava kiyana ekane )

oyage no (1) commet eka weredi! චාලක ශක්තිය 300%කින් ඉහළ nanavanava kiyana eka samana wenne na 3 gunyakin vedi wenava kiyana ekata.eken kiyanne 3n gunayak karanava kiyana ekai !


othana kiyanne
(1/2 my^(2)) / (1/2 mx^2) = 300%

comment (2) wka weredi ! anithva hari! tikak kalpana karala balanna!

 

[Ed.Win]

ok thanks

 

[sandun36]

ok thanks

ur welcome ! but i accept there's a possibility of understanding of this sum as u did, since able to predict if this is came in a al paper most probably marks will be given to the both answers! But better to be on safe hands with majority's thinking!

Wish u good luck! At the same time it's advisable to read Rosa sir's books about past papers to have a better understanding on physics!

 

[Ed.Win]

ur welcome ! but i accept there's a possibility of understanding of this sum as u did, since able to predict if this is came in a al paper most probably marks will be given to the both answers! But better to be on safe hands with majority's thinking!

Wish u good luck! At the same time it's advisable to read Rosa sir's books about past papers to have a better understanding on physics!

yeah,but still i have this problem,it says "chalaka shakthi 300% ihala nanvai",then shouldn't it be the difference between the "aarambaka" and "avasaana" kinetic energy.

 

[sandun36]

yeah,but still i have this problem,it says "chalaka shakthi 300% ihala nanvai",then shouldn't it be the difference between the "aarambaka" and "avasaana" kinetic energy.

in here matter is with the % sign brother , when ever using a % sign we are used to compare something with another directly! In here at the first moment u glance at 300% u've to understand it's a comparison between first & last!

hw ever don't think much abt this matter & waste ur valuable time , i agree there's a problem with the language of this sum!

 

[Ed.Win]

in here matter is with the % sign brother , when ever using a % sign we are used to compare something with another directly! In here at the first moment u glance at 300% u've to understand it's a comparison between first & last!

hw ever don't think much abt this matter & waste ur valuable time , i agree there's a problem with the language of this sum!

thanks bro,i think you have spent more than an hour to explain this,thanks a lot.it's time to move on from here.thanks again

may your all dreams come true

 

[sandun36]

thanks bro,i think you have spent more than an hour to explain this,thanks a lot.it's time to move on from here.thanks again

may your all dreams come true

avulak na kolla may dawas wala api gederama tham inne , faculties okkoma vahalane , seeu!