Latest ads

Baseus PI LITE INDOOR CAMERA
- ErMurazor
- Updated: Yesterday at 12:26 PM
Ad icon
Colombo Hard Disk For Sale
- mazza
- Updated: Saturday at 10:23 PM
land for sale
- justasking
- Updated: Saturday at 9:32 AM
AMD AM 5 Ryzen setup
- prabodhamadusanka
- Updated: Thursday at 12:56 PM
Gampaha ACER OKW223 Wired RGB Keyboard
- chint
- Updated: Thursday at 10:17 AM

Reply to thread

Message: <blockquote data-quote="1118lakmalkumara" data-source="post: 31650888" data-attributes="member: 204945">Question 91, 2, 9, 4, 25, ___, 7(a) 36  (b) 33  (c) 27  (d) 35SolutionNote: the small “²” on 2, 4 and 7 doesn’t show in the print, so I’ve read the sequence as 1, 2², 9, 4², 25, ___, 7².<ol> <li data-xf-list-type="ol">Write each term as a square: 1², 2², 3², 4², 5², ___, 7².</li> <li data-xf-list-type="ol">The bases go 1, 2, 3, 4, 5, ?, 7, so the missing base is 6.</li> <li data-xf-list-type="ol">Missing term = 6² = 36.</li> </ol>Final Answer: (a) 36<hr />Question 35BDAC : FHEG :: NPMO : ___(a) QTRS  (b) RQTS  (c) TRQS  (d) RTQSSolution<ol> <li data-xf-list-type="ol">In alphabet positions, B D A C = 2, 4, 1, 3 and F H E G = 6, 8, 5, 7.</li> <li data-xf-list-type="ol">Each letter moves forward 4 (2→6, 4→8, 1→5, 3→7).</li> <li data-xf-list-type="ol">N P M O = 14, 16, 13, 15.</li> <li data-xf-list-type="ol">Add 4 to each: 18, 20, 17, 19 = R, T, Q, S.</li> </ol>Final Answer: (d) RTQS<hr />Question 36FxyZ : YyxF :: AefM : ___(a) RefL  (b) AefL  (c) LefL  (d) LfeASolution<ol> <li data-xf-list-type="ol">Reverse FxyZ to get ZyxF.</li> <li data-xf-list-type="ol">Compared with YyxF, only the first letter changes: Z → Y, one letter back.</li> <li data-xf-list-type="ol">So the rule is: reverse the word, then move the first letter back by 1.</li> <li data-xf-list-type="ol">Reverse AefM to get MfeA.</li> <li data-xf-list-type="ol">Move M back one to L, giving LfeA.</li> </ol>Final Answer: (d) LfeA<hr />Questions 17 to 22A Travel Agent is arranging sight seeing tours in the following locations L, M, N, O, P, Q, R, S, and T. Each tour has the following conditions:<ol> <li data-xf-list-type="ol">If M is included, both Q and R must be included.</li> <li data-xf-list-type="ol">P can be included only if O is included.</li> <li data-xf-list-type="ol">If Q is included, M must be included along with either N or T or both.</li> <li data-xf-list-type="ol">P and Q cannot be combined together.</li> <li data-xf-list-type="ol">O, R and T cannot be combined together.</li> <li data-xf-list-type="ol">N, S and R cannot be combined together.</li> <li data-xf-list-type="ol">L and R cannot be combined.</li> </ol>Rules 5 and 6 mean all three can’t be in the same tour. Any two of them together is fine.<hr />Question 17If M is included in a tour, the minimum number of other cities that must be included is(a) 3  (b) 4  (c) 5  (d) 6Solution<ol> <li data-xf-list-type="ol">Rule 1: M is in, so Q and R must be in.</li> <li data-xf-list-type="ol">Rule 3: Q is in, so N or T must be in.</li> <li data-xf-list-type="ol">No other rule forces a city in.</li> <li data-xf-list-type="ol">The minimum is Q + R + (N or T) = 3 cities.</li> </ol>Final Answer: (a) 3<hr />Question 18Which of the following tours cannot be included with P?(a) L  (b) M  (c) N  (d) OSolution<ol> <li data-xf-list-type="ol">Rule 4: P is in, so Q is out.</li> <li data-xf-list-type="ol">Rule 1: M needs Q, so M is out.</li> <li data-xf-list-type="ol">L, N and O don’t clash with P. O is actually required with P.</li> </ol>Final Answer: (b) M<hr />Question 19Which of the following is an acceptable tour group?(a) M N O P  (b) M N Q R  (c) M N Q S  (d) L M Q RSolution<ol> <li data-xf-list-type="ol">(a) M needs Q and R, and both are missing ✗</li> <li data-xf-list-type="ol">(b) M has Q and R, Q has M and N, and nothing clashes ✓</li> <li data-xf-list-type="ol">(c) M needs R, which is missing ✗</li> <li data-xf-list-type="ol">(d) L is with R ✗ (and Q has neither N nor T)</li> </ol>Final Answer: (b) M N Q R<hr />Question 20Which of the following would have to be removed from a group to form an acceptable tour?(a) M  (b) Q  (c) O  (d) RSolutionNote: the question doesn’t name the group, so I’ve taken it as all nine locations.<ol> <li data-xf-list-type="ol">With all nine included, rules 4, 5, 6 and 7 are broken.</li> <li data-xf-list-type="ol">R is in three of those clashes (rules 5, 6 and 7), so remove R.</li> <li data-xf-list-type="ol">M needs R, so M goes. Q needs M, so Q goes too, which also fixes rule 4.</li> <li data-xf-list-type="ol">That leaves L, N, O, P, S, T, which is an acceptable tour.</li> <li data-xf-list-type="ol">Removing M, Q or O instead still leaves either O, R, T or N, S, R together.</li> </ol>Final Answer: (d) R<hr />Question 21Which of the following can be an acceptable tour if one more destination is added?(a) M, P, Q  (b) M, Q, R  (c) N, S, R  (d) R, T, PSolution<ol> <li data-xf-list-type="ol">(a) P with Q is a clash, and adding a city can’t remove it ✗</li> <li data-xf-list-type="ol">(b) The only thing missing is N or T. Adding N gives M, N, Q, R ✓</li> <li data-xf-list-type="ol">(c) N, S and R together is a clash ✗</li> <li data-xf-list-type="ol">(d) P needs O, but adding O puts O, R and T together ✗</li> </ol>Final Answer: (b) M, Q, R<hr />Question 22How many destinations can be used for a tour consisting of one city only?(a) 3  (b) 4  (c) 5  (d) 6Solution<ol> <li data-xf-list-type="ol">M needs Q and R, P needs O, and Q needs M, so these 3 can’t be alone.</li> <li data-xf-list-type="ol">L, N, O, R, S and T don’t need any other city, so each can be alone.</li> <li data-xf-list-type="ol">9 − 3 = 6.</li> </ol>Final Answer: (d) 6</blockquote>

Verification: Asuwa dahayen wadi kalama keeyada?

Top Bottom