Search
Search titles only
By:
Search titles only
By:
Log in
Register
Search
Search titles only
By:
Search titles only
By:
Menu
Install the app
Install
Forums
New posts
All threads
Latest threads
New posts
Trending threads
Trending
Search forums
What's new
New posts
New ads
New profile posts
Latest activity
Free Ads
Latest reviews
Search ads
Members
Current visitors
New profile posts
Search profile posts
Contact us
Latest ads
Ad icon
Video Content Creator
pramukag
Updated:
Today at 6:10 AM
Ad icon
QA Engineer Intern
pramukag
Updated:
Today at 6:07 AM
Ad icon
Sell your Land, House on idamata.lk for FREE
sajith.xp.pk
Updated:
Thursday at 9:03 AM
Handmade Character Soft Toys
anil1961
Updated:
Tuesday at 2:11 PM
Bodim.lk out now !
Manoj Suranga Bandara
Updated:
Jun 21, 2026
Electronics
Vehicles
Property
Search
Reply to thread
Forums
General
ElaKiri Talk!
hyperbolic funtion
Get the App
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Message
<blockquote data-quote="07sanjeewakaru" data-source="post: 23053538" data-attributes="member: 460140"><p><span style="font-size: 12px"><strong>oka thama cosh,sinh wala artha dak weema.....</strong></span></p><p><span style="font-size: 12px"><strong>onama z complex number ekakata ex {exp[x]} mehema artha dakkuwahama...</strong></span></p><p><span style="font-size: 12px"><strong></strong></span><span style="font-size: 12px"><strong><img src="https://wikimedia.org/api/rest_v1/media/math/render/svg/b83befa1c3c14ee8852940a098d90ba2aacef0c5" alt="" class="fr-fic fr-dii fr-draggable " style="" /></strong></span><span style="font-size: 12px"><strong></strong></span></p><p><span style="font-size: 12px"><strong>sin[x]= ( exp[ix] - exp[-ix ])/2</strong></span></p><p><span style="font-size: 12px"><strong>cos[x]= ( exp[ix] + exp[-ix ])/2; </strong></span></p><p><span style="font-size: 12px"><strong><em>i</em>2 = −1..[i kiyanne -1ke wargamulaya....]</strong></span></p><p> <span style="font-size: 12px"><strong>sinh(x) = ( exp[x] - exp[-x ])/2</strong></span></p><p><span style="font-size: 12px"><strong>cosh(x) = ( exp[x] + exp[-x] )/2</strong></span></p><p><span style="font-size: 12px"><strong></strong></span></p><p><span style="font-size: 12px"><strong>thrikonayen sin cos function wala artha dakwanta puluwan sulu kona walata witharai.....maha kona walata yaddi projection walata yanta wenawa...ithath passe complex number wala sin cos [sin[1+i]wage]walata artha dakwanta wenne uda thiyana exp[x] asurin....</strong></span></p><p><span style="font-size: 12px"><strong>artha dakweem generalise karanawa....</strong></span></p><p><span style="font-size: 12px"><strong>thrikonayen artha dakwana uththarema thama enne udin thiyena artha dakweemenet....</strong></span></p><p><span style="font-size: 12px"><strong></strong></span></p><p><span style="font-size: 12px"><strong></strong></span></p></blockquote><p></p>
[QUOTE="07sanjeewakaru, post: 23053538, member: 460140"] [SIZE=3][B]oka thama cosh,sinh wala artha dak weema..... onama z complex number ekakata ex {exp[x]} mehema artha dakkuwahama... [/B][/SIZE][SIZE=3][B][IMG]https://wikimedia.org/api/rest_v1/media/math/render/svg/b83befa1c3c14ee8852940a098d90ba2aacef0c5[/IMG][/B][/SIZE][SIZE=3][B] sin[x]= ( exp[ix] - exp[-ix ])/2 cos[x]= ( exp[ix] + exp[-ix ])/2; [/B][/SIZE] [SIZE=3][B][I]i[/I]2 = −1..[i kiyanne -1ke wargamulaya....] sinh(x) = ( exp[x] - exp[-x ])/2 cosh(x) = ( exp[x] + exp[-x] )/2 thrikonayen sin cos function wala artha dakwanta puluwan sulu kona walata witharai.....maha kona walata yaddi projection walata yanta wenawa...ithath passe complex number wala sin cos [sin[1+i]wage]walata artha dakwanta wenne uda thiyana exp[x] asurin.... artha dakweem generalise karanawa.... thrikonayen artha dakwana uththarema thama enne udin thiyena artha dakweemenet.... [/B][/SIZE] [/QUOTE]
Insert quotes…
Verification
Winadiyakata thappara keeyak tibeda?
Post reply
Top
Bottom