ahamednishadh said:<b>
k found da answer
lets say thus
triangle=T , circle=C & square=S
so according to da 1st balanceT+2S=3Caccording to da 2nd balanceT+C=6Saccording to da 3rd balance2S+C=?therefore da first two equatins above can also be writen thus:3C-2S=T --- (Eq 1)therefore subtracting Eq 2 from Eq 1 can be shown thus
6S-C=T --- (Eq 2)
1. 3C - 2S - (6S - C) = T - Tso we now know that 1 Circle is equal to 2 Squares.
2. 3C - 2S - 6S + C = 0
3. 4C - 8S = 0
4. therefore 4C = 8S
5. therefore C = 2S
therefore in da first scale we c 1 Triangle + 2 Squares = 3 Cirlces
so if 1 Circle and 2 Squares are taken off from the first scale it will still balance which means that 1 Triangle = 2 Circles
so in da 3rd scale we c 1 Cirlce and 2 Squares which is also equal to 2 Circles
so as we have found out dat 2 Circles = 1 Triangle
then 1 Circle + 2 Squares = 1Triangle
Bro answer eka hari neda???????????
</b>
very nice ......






