its amazing.cn u do diz

[shan_n95]

guyz cn u proove diz

1+1=1

its easy

 

[chathumal]

ekai ekai ekata ekathu kalama ekai thamai.

 

[shan_n95]

ekai ekai ekata ekathu kalama ekai thamai.

hoda ex ekak deepan..ohoma baaa

 

[ztnap]

a = 1
b = 1

a = b
a2 = b2
a2 - b2 = 0
(a-b)(a+b) = 0
(a-b)(a+b)/(a-b) = 0/(a-b)
1(a+b) = 0
(a+b) = 0
1 + 1 = 0
2 = 0

Now let's divide both sides by 2, and we get:

1 = 0

Now add 1 to each side (1+1 = 0+1) then you'll get:

1 + 1 = 1

~Z~

 

[OneUnited]

a = 1
b = 1

a = b
a2 = b2
a2 - b2 = 0
(a-b)(a+b) = 0
(a-b)(a+b)/(a-b) = 0/(a-b)
1(a+b) = 0
(a+b) = 0
1 + 1 = 0
2 = 0
1 = 0
1 + 1 = 1

Someone Already proved it before me! Nice!

 

[kosandpol]

Assume x=1 and y =1
therefore : x=y
so : x^2 = y^2 - squares of equal numbers are also equal
therefore : x^2-y^2 = 0 - substract y^2 from both sides
which means : (x-y)*(x+y)=0
therefore : (x-y)*(x+y)/(x-y)=0/(x-y) - divide both sides by (x-y)
thus : 1 * (x+y) = 0
so : x+y =0
since x=1 and y=1 : 1+1 =0
thus : 2= 0
therfore : 2/2 = 0 /2 - divide both sides by 2
thus : 1 = 0
by adding 1 to both sides : 1+1 = 0+1
thus : 1+1=1

 

[9.57]

Great stuff! somebody has already solved this know..

we need more of this kind of numbering stuff

 

[ni_shi2005]

ogollanta pissu!!
1+1 = 11

skole giya nedda kattiya?

 

[kosandpol]

Now can someone point out the fallacy in the method of how 1+1=1 was proved ?

 

[kalanaweerlk]

a = 1
b = 1

a = b
a2 = b2
a2 - b2 = 0
(a-b)(a+b) = 0
(a-b)(a+b)/(a-b) = 0/(a-b)
1(a+b) = 0
(a+b) = 0
1 + 1 = 0
2 = 0

Now let's divide both sides by 2, and we get:

1 = 0

Now add 1 to each side (1+1 = 0+1) then you'll get:

1 + 1 = 1

~Z~

u have composed this answer very cleverly n clearly
problem solved

but just to show how dis step happened to those who didn't understand dis

a2 - b2 = 0
(a-b)(a+b) = 0

(a-b)(a+b)=a2+ab-ab-b2
=a2-b2

so, (a-b)(a+b)=a2-b2

 

[Tharindu Chat]

Daz finished before i came

Hw Bad????????

 

[kosandpol]

Daz finished before i came

Hw Bad????????

Well , then you can continue by showing the fallacy in the method used to prove that 1+1=1

 

[I.Udara]

According 2 da Boolean Algebra Dis is correct!
1+1=1

 

[nad253]

ne kattiyatama pissu 1+1 = 2 i ne

 

[amiya]

1 + 1 = 1 + 1

Nadda Nadda Nadda Man Ahanne ?

 

[x-pert]

Assume x=1 and y =1
therefore : x=y
so : x^2 = y^2 - squares of equal numbers are also equal
therefore : x^2-y^2 = 0 - substract y^2 from both sides
which means : (x-y)*(x+y)=0
therefore : (x-y)*(x+y)/(x-y)=0/(x-y) - divide both sides by (x-y)
thus : 1 * (x+y) = 0
so : x+y =0
since x=1 and y=1 : 1+1 =0
thus : 2= 0
therfore : 2/2 = 0 /2 - divide both sides by 2
thus : 1 = 0
by adding 1 to both sides : 1+1 = 0+1
thus : 1+1=1

x-y = 1-1 becomes 0 right?

If you divide any number by 0, it becomes infinity hehe just playing with the symbols

And according to mathematical theories, you cant equalise 2 different equations to zero. Because 0 != 0

(Well.. I did Bio for A/Ls so not too sure )

 

[kalanaweerlk]

Well , then you can continue by showing the fallacy in the method used to prove that 1+1=1

y wont u continue mister

 

[ztnap]

y wont u continue mister

You cant divide both sides of an equation by zero..

a-b = 0

So this part is wrong.. (a-b)(a+b)/(a-b) = 0/(a-b)



~Z~

 

[mentor_ub]

You cant divide both sides of an equation by zero..

a-b = 0

So this part is wrong.. (a-b)(a+b)/(a-b) = 0/(a-b)



~Z~

true....

 

[mentor_ub]

Just rotate the '+' mark to 'x'...
so it will be as 1X1=1..done.....