oyata ona mokak hari base ekaka thiyena number ekak thawa base ekakata harawannada?
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Java Problem
- Thread starter sachii
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oyata ona mokak hari base ekaka thiyena number ekak thawa base ekakata harawannada?
hello im not a java expert & languages are mixed up now
but did some, i dnt have java so can't compile it. there may be many syntax errors fix them & just implement converting methods lol u DO THE MATH
Code:
#import Java.util.*
class NumberBaseConverter
{
public static void main (String [] args)
{
int number, base , decimal;
Scanner sc = new Scaner();
System.out.println("Eneter No: ");
number = sc.nextInt();
System.out.println("Base of the Entered Number: ");
base = sc.nextInt();
switch (base)
{
case 2:
decimal = binaryToDecimal(number);
break;
case 8:
decimal = octalToDecimal(number);
break;
case 16:
decimal = hexaToDecimal(number);
break;
default:
System.out.println("Invalid Input, get a life :P ");
break;
}
System.out.println("Entered Number in decimal = " + decilmal );
}
public static int binaryToDecimal (int number)
{
return ;
}
public static int octalToDecimal (int number)
{
return ;
}
public static int hexaToDecimal (int number)
{
return ;
}
}
this is the answer
hello im not a java expert & languages are mixed up now
but did some, i dnt have java so can't compile it. there may be many syntax errors fix them & just implement converting methods lol u DO THE MATH
Code:#import Java.util.* class NumberBaseConverter { public static void main (String [] args) { int number, base , decimal; Scanner sc = new Scaner(); System.out.println("Eneter No: "); number = sc.nextInt(); System.out.println("Base of the Entered Number: "); base = sc.nextInt(); switch (base) { case 2: decimal = binaryToDecimal(number); break; case 8: decimal = octalToDecimal(number); break; case 16: decimal = hexaToDecimal(number); break; default: System.out.println("Invalid Input, get a life :P "); break; } System.out.println("Entered Number in decimal = " + decilmal ); } public static int binaryToDecimal (int number) { return ; } public static int octalToDecimal (int number) { return ; } public static int hexaToDecimal (int number) { return ; } }
ha ha big thanks for the help
me there is a for loop ne then it easy according that instruct
pseudo code
Code:
START
NUMERIC base,numbertemp,temp,i,numInt
NUMERIC temp2=0
CHAR[100] number
DISPLAY "enter the base number"
ACCEPT base
IF base LESS THAN 10 THEN
DISPLAY "enter the number"
ACCEPT number
NUMERIC i= length(number)-1
FOR EACH num IN number
numInt = (NUMERIC)num
temp = base ^ i
temp2 = temp2 + (temp * numInt )
i = i-1;
END FOR EACH
END IF
DISPLAY "the answer is for " + base + " base is " + temp2
END
Last edited:
ha ha big thanks for the help
me there is a for loop ne then it easy according that instruct
yeah u shud use loops to get decimal answer fill those methods for that, i guess Topaa has given a good pseudocode...
Code:
import java util;
class Test {
scanner sc = new scanner(system.in);
s.out("Entere nuber");
string x= sc.nextInt();
enter nubmer
s.out ("enter BASE");
int base = sc.next.Int();
int t = array () = new
for (int i =0 ; i< numberlengt ; i++);
Code:
import java.util.*;
/**
*
* @author Chinthy
*/
public class Base
{
public static void main(String args[])
{
int number;
double val = 0;
int length;
int base;
System.out.println("Enter value: ");
Scanner scan1 = new Scanner(System.in);
number = scan1.nextInt();
length = String.valueOf(number).trim().length();
System.out.println("Enter base value: ");
Scanner scan2 = new Scanner(System.in);
base = scan2.nextInt();
while(number>0)
{
double [] rem = new double[length];
for(int i =0;i<length;i++)
{
rem[i] = number % 10;
number = number / 10;
val = val + (rem[i]*(Math.pow(base, i)));
}
}
System.out.println("Value: "+val);
}
}Checked two three values. Harida danne na dan haduwe... i think this should work.
Last edited:
ye this is okChecked two three values. Harida danne na dan haduwe... i think this should work.Code:import java.util.*; /** * * @author Chinthy */ public class Base { public static void main(String args[]) { int number; double val = 0; int length; int base; System.out.println("Enter value: "); Scanner scan1 = new Scanner(System.in); number = scan1.nextInt(); length = String.valueOf(number).trim().length(); System.out.println("Enter base value: "); Scanner scan2 = new Scanner(System.in); base = scan2.nextInt(); while(number>0) { for(int i =0;i<length;i++) { double [] rem = new double[length]; rem[i] = number % 10; number = number / 10; val = val + (rem[i]*(Math.pow(base, i))); } } System.out.println("Value: "+val); } }
told to do this way thanks brother
ye this is ok
told to do this way thanks brother
Did a slight adjustment. That rem[] array declaration should come before the for loop. Mehema tibbath hari coz the val variable is carried onto the next loop and the new value is preserved. But this is better so it doesn't create a new array each time the loop runs.
This is the Answer, but i have not include conditional statements to check weather the inputs are correct, for correct inputs this works fine
here is the code :
public class Convertor {
public Convertor() {
}
public static void main(String args []){
Convertor conv = new Convertor();
int decimalValue = conv.getDecimal("121",3);
System.out.println("Decimal value = " + decimalValue);
}
public int getDecimal(String num , int base){
char [] numbers = num.toCharArray();
int sum = 0 ;
for (int i = numbers.length-1; i >= 0; i--) {
int val = Integer.parseInt(numbers+"");
int order = (numbers.length-1) - i;
int ordermul = (int) Math.pow((double)base, order);
sum = sum +ordermul*val;
}
return sum;
}
}
uni eke 1st year kalee.. eva itin exam walata vtraneee.... 
.. C# nam puluwan... bumpsssssssssssssssssssssss.......
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