MACHAN GAANAK THIYENAWA ....UDAAW KARAPALLAKOO

[haarshlife]

ayyala ganak thiyenawa ,...puluwan kenek help ekak deepankoo

find the critical numbers and the open intervals on which the function is increasing or decreasing....

f(x) = 2x-3

 

[haarshlife]

Ekekwath danne naddooo....

 

[Proxies]

Danne ne bang...Ganan fail ban...

 

[gayancc]

dan owa amathakai banzz

 

[random]

f(x)=2x-3
=2

criticle Value f'(x)=0
x=-2
(-&,-2)(-2,&)

(-&,-2) | (-2,&)
f'(-2)<0 | f'(0)>0
Decreasing Increasing

 

[[email protected]]

f(x)=2 nd f(x)=1 ne?

 

[haarshlife]

f(x)=2x-3
=2

criticle Value f'(x)=0
x=-2
(-&,-2)(-2,&)

(-&,-2) | (-2,&)
f'(-2)<0 | f'(0)>0
Decreasing Increasing

thnXXX kollo... godak pin

 

[ra20002]

f(x) = 2x-3

this is a straight line , there is no incresing discresing

becz the derivative is 2

and the slope is positive also cut the y-axis in -3

 

[random]

Thats the way we did in MIT....

 

[ra20002]

Thats the way we did in MIT....

how can it possible becz this is not a curve this is just a straight line

 

[haarshlife]

f(x) = 2x-3

this is a straight line , there is no incresing discresing

becz the derivative is 2

and the slope is positive also cut the y-axis in -3

machan ethakota random ge answer eka upset da...

 

[random]

haarshlife Check the examples in U're MIT text Book...

 

[haarshlife]

haarshlife Check the examples in U're MIT text Book...

machan meka decreasing and increasing neda ... straight line ekak nemeine

 

[sclemont]

mata oka sinhalen kiyanna barida???????

 

[mawella]

totally confuse :S:S

 

[haarshlife]

machanla mata thawa poddak explain karanna puluwanda

 

[sgmdarshana]

machan meka poddak check karala balapan


f(x)=2x-3
deravative is [ f'(x) ] = 2
there is no critical value.
you get critical values if there is indipendent variable in the deravetive of f(x).

this eqation like y=mx+c
y= f(x)
m= 2
c= -3

when x=0 then
f(x)=-3
when f(x)=0 then
x=3/2=1.5

here is the graph
http://img9.imageshack.us/img9/8642/madu.jpg

 

[haarshlife]

machan meka poddak check karala balapan


f(x)=2x-3
deravative is [ f'(x) ] = 2
there is no critical value.
you get critical values if there is indipendent variable in the deravetive of f(x).

this eqation like y=mx+c
y= f(x)
m= 2
c= -3

when x=0 then
f(x)=-3
when f(x)=0 then
x=3/2=1.5

here is the graph
<a href="http://img9.imageshack.us/my.php?image=madu.jpg" target="_blank"><img src="http://img9.imageshack.us/img9/8642/madu.th.jpg" border="0" alt="Free Image Hosting at www.ImageShack.us" /></a><br /><br /><a href="http://img604.imageshack.us/content.php?page=blogpost&files=img9/8642/madu.jpg" title="QuickPost"><img src="http://imageshack.us/img/butansn.png" alt="QuickPost" border="0"></a> Quickpost this image to Myspace, Digg, Facebook, and others!

thnXXX machan godaaak pin... bt cant c da graph machn

 

[sgmdarshana]

thnXXX machan godaaak pin... bt cant c da graph machn

sorry machan.
dan poddak balapan

 

[amiya]

f(x) = 2x-3

this is a straight line , there is no incresing discresing

becz the derivative is 2

and the slope is positive also cut the y-axis in -3