MACHAN GAANAK THIYENAWA ....UDAAW KARAPALLAKOO

[haarshlife]

sorry machan.
dan poddak balapan

ela ela thnXX machan...issella x=o kala... eeta passe f(x) =0 karanne ayi machan

 

[aragon]

ayyala ganak thiyenawa ,...puluwan kenek help ekak deepankoo

find the critical numbers and the open intervals on which the function is increasing or decreasing....

f(x) = 2x-3

No critical values involing. F'(x) =\ 0 for all possible x values.
But we can simply say that the function is increasing. when u increase the x value f(x) value goes up and via versa.

 

[funhasitha]

hasitha

hi machan

 

[haarshlife]

No critical values involing. F'(x) =\ 0 for all possible x values.
But we can simply say that the function is increasing. when u increase the x value f(x) value goes up and via versa.

ela machan ethakota critical values hoyanna wenne f'(x) = variable ekak awoth witharada

ex: f'(x)= 2x-5

 

[haarshlife]

hi machan

hi hi machan WC 2 elakiri

 

[aragon]

ela machan ethakota critical values hoyanna wenne f'(x) = variable ekak awoth witharada

ex: f'(x)= 2x-5

Ow macho..mehemai..dan critical point ekak kiyanne function eke 1st derivative eka zero wena pointz tikatane..(habei ema wenne function eke degree eka (mathraya) >=1 nam witharai) e kiyanne f(x)=5 wage ewata meka true neha)
f'(x)= 2x-5 nam x=2.5 di critical point ekak enawa..

 

[haarshlife]

Ow macho..mehemai..dan critical point ekak kiyanne function eke 1st derivative eka zero wena pointz tikatane..(habei ema wenne function eke degree eka (mathraya) >=1 nam witharai) e kiyanne f(x)=5 wage ewata meka true neha)
f'(x)= 2x-5 nam x=2.5 di critical point ekak enawa..

ok machan thnXXX

 

[aragon]

ok machan thnXXX

U r welcum ..