power ofcan u explain what '^' stands for in your equation? is it for 'to the power of..' ?
ow ow balaya thamai. mata hithena widiyata awakalanayen thamai hadanna ona..Awakalanayada?
Bawa penwanna 1a hariyata danna balanna....
Me '^' balayada?
y = (Acospx + Bsinpx)/x^q (A, B, p & q niyatha agayan) namMe answer 1a(Bawa penwanna) 1a aye chq karala post karanavada?![]()
y = (Acospx + Bsinpx)/x^q (A, B, p & q niyatha agayan) nam
(p^2 + (q^2-q)/x^q)y = 0 bawa penwanna
sry kollamm awulak ne sin cos nam 2parak awakalanaya karama ain karanna puluwan....Hmmm therenne na bunz....awakalanaya wenna bae...answr 1e Sin , Cos ayin kala hatì theren
Natha....sry kolla
machan mokakda apahedili..gana pahadili madi hadanna puluwan awakalanayen...
mm awulak ne sin cos nam 2parak awakalanaya karama ain karanna puluwan....
d2y/dx2 thamai ain karanna beri....
qy(q-1)x^(q-2) + 2qx^(q-1)dy/dx +x^qd2y/dx2 + p^2(Acospx + Bsinpx) = 0machn 2 parak awakalanaya karala apu step poddk dapan balanna...