Maths guys wanted solving.

[costaxxx]

(x-3) is a factor of 3x^3 + 8x^2 + kx - 60
fin the value of k
pls can some one o it for me?

 

[costaxxx]

kastiya bump akak wath daplko danne nathnm>pls

 

[Tom Riddle]

Using the remainder theorem, substituting x=3

3*3^3+8*3^2+3k-60=0
3k=-93
k=-31

 

[pupudu]

let f(x)=3x^3+ 8x^2 +kx-60
if x-3 is a factor then
f(3)=0
that is 3(3)^3 +8(3)^2 +k(3) -60 =0
81+72+3k-60=0
3k=-93
k=-31

 

[pupudu]

Using the remainder theorem, substituting x=3

3*3^3+8*3^2+3k-60=0
3k=-93
k=-31

uba maths karana ekek unata 3n bedanda bane ubata

 

[sandun36]

-31 y rep+ ekakvath deepan!

3x^3 + 8x^2 -31x - 60 = (x-3)(3x^2+17x+20)

 

[costaxxx]

Using the remainder theorem, substituting x=3

3*3^3+8*3^2+3k-60=0
3k=-93
k=-31

tnk u

 

[sandamal666]

3x^3 + 8x^2 + kx - 60
= (x-3)(3x^2 + 17x + [51+k])

(51+k)*(-3) = -60 (Constants should be equal on both sides)
51+k = 20
k = 31.

 

[mechdials]

x-3 සාධකයක් නම්, x=3 දාපුවම f(x)=0,එනම් f(3)=0
3(3)^3 + 8(3)^2 + 3k -60=0
k=-31

 

[nadimal]

x-3 සාධකයක් නම්, x=3 දාපුවම f(x)=0,එනම් f(3)=0
3(3)^3 + 8(3)^2 + 3k -60=0
k=-31

oya thiyenne pahadilwama

 

[costaxxx]

tnk u all hope all got rep++