programme logic eka kiyanna menna me examlpe ekata??

[amila.ela]

the input is: 9087236781
so the result must be in 1 digit like this
9+0+8+7+2+3+6+7+8+1=51>>>>5+1= 6

give me progaming logic about that????

 

[kingdewi]

අම්මෝ මචෝ..මේක මගේ ඇඟේ නැති සබ්ජෙක්ට් එකක්..ප්‍රෝග්‍රැමින්!
සමාවෙන්ටෝනෙ!

 

[nagaya]

while length=1 wenakan substring kadila ewage values ekatu wenna lyanna

 

[amila.ela]

while length=1 wenakan substring kadila ewage values ekatu wenna lyanna

machan poddak liyala pennakoo

 

[nagaya]

machan poddak liyala pennakoo

poddk hitpn macho lyala denna

 

[buddhi9077]

hmm oluwata enne na banzz apu gaman gahannam

 

[viraj_slk]

One possible solution to think of

the input is: 9087236781
so the result must be in 1 digit like this
9+0+8+7+2+3+6+7+8+1=51>>>>5+1= 6

give me progaming logic about that????

Good to see that u have asked for the logic rather than a code.

Here's one way I thought of to do it:
first assign ur number to a variable as integer :
x = 9087236781;

then convert the same number to a string value. This is so that I can loop through each character.
str = (string_cast) x;

now str = '9087236781';
so..for example: str[0] is equal to 9;

now use a loop like this to keep adding the numbers together UNTIL the total is less than or equal to 9.

while (x > 9)
{
   str = (string_cast) x;
   len = length(x); // the length of the number 
   
   total = 0;
   for (i = 0; i < len; i++) 
   {
      total += (integer_cast)str[i];
   }

   x = total;
}

finally.. when the loop gets finished, 'x' will have a single digit value that is less than or equal to 9, and is also the summation of numbers in '9087236781'

Let me know if u need a bit more help to clarify this one.

 

[nagaya]

import java.util.Scanner;
class logic{
public static void main(String[] args){
int x=0,y=0;
String num=null;
Scanner in = new Scanner(System.in);
num = in.nextLine();
while(num.length() > 1){
y=0;
for (x=0;x<num.length();x++)
{
y += Integer.parseInt(num.substring(x,x+1));
}
num = Integer.toString;
}
System.out.println;
}
}

 

[viraj_slk]

import java.util.Scanner;
class logic{
public static void main(String[] args){
int x=0,y=0;
String num=null;
Scanner in = new Scanner(System.in);
num = in.nextLine();
while(num.length() > 1){
y=0;
for (x=0;x<num.length();x++)
{
y += Integer.parseInt(num.substring(x,x+1));
}
num = Integer.toString;
}
System.out.println;
}
}

Good solution bro. Although I can hardly remember any java now I can make out the logic in ur code. You have done the same thing as I have, but instead u have used the length of the final solution (which should be 1) as the controller for the loop, where as I used the condition that value must be less than or equal to 9 as the condition to continue the loop.

Good stuff.

 

[nagaya]

Good solution bro. Although I can hardly remember any java now I can make out the logic in ur code. You have done the same thing as I have, but instead u have used the length of the final solution (which should be 1) as the controller for the loop, where as I used the condition that value must be less than or equal to 9 as the condition to continue the loop.

Good stuff.

Yep bro!I also noticed that,that's the only difference,I can't remember much C now to do this,that's why i used Java

 

[viraj_slk]

Yep bro!I also noticed that,that's the only difference,I can't remember much C now to do this,that's why i used Java

I don't think there is such thing as 'string_cast' in C, is there? think u can directly assign an integer to a string without casting in C. can't remember much of C either

anyway, so i jst posted the logic. almost any program should be programmable using any language once u get the logic right.

 

[nagaya]

I don't think there is such thing as 'string_cast' in C, is there? think u can directly assign an integer to a string without casting in C. can't remember much of C either

anyway, so i jst posted the logic. almost any program should be programmable using any language once u get the logic right.

nope there is nothing as string_cast on C,and there is no String on C either,it's just an array of char,yep you're absolutely correct,once we thought algorithm,the programmer can code it using any language,btw,it seems thread starter is missing,

 

[amilabanuka]

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class NumberProcessor {

    public static void main(String[] args) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String input;
        try {
            input = reader.readLine();
        } catch (IOException ex) {
            input = "";
        }
        int number;
        do {
            number = processString(input);
            input = String.valueOf(number);
        } while (input.length() > 1);
        System.out.println("summed result is : " + number);

    }

    private static int processString(String input) {
        int value = 0;
        for (int i = 0; i < input.length(); i++) {
            value += Integer.parseInt(String.valueOf(input.charAt(i)));
        }
        return value;
    }
}

hope this help..

 

[viraj_slk]

nope there is nothing as string_cast on C,and there is no String on C either,it's just an array of char,yep you're absolutely correct,once we thought algorithm,the programmer can code it using any language,btw,it seems thread starter is missing,

oh yes, string == char[] in C. thanks for reminding

 

[amila.ela]

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class NumberProcessor {

    public static void main(String[] args) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String input;
        try {
            input = reader.readLine();
        } catch (IOException ex) {
            input = "";
        }
        int number;
        do {
            number = processString(input);
            input = String.valueOf(number);
        } while (input.length() > 1);
        System.out.println("summed result is : " + number);

    }

    private static int processString(String input) {
        int value = 0;
        for (int i = 0; i < input.length(); i++) {
            value += Integer.parseInt(String.valueOf(input.charAt(i)));
        }
        return value;
    }
}

hope this help..

mata meka C# walin liyala dennakooo??

 

[amila.ela]

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class NumberProcessor {

    public static void main(String[] args) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String input;
        try {
            input = reader.readLine();
        } catch (IOException ex) {
            input = "";
        }
        int number;
        do {
            number = processString(input);
            input = String.valueOf(number);
        } while (input.length() > 1);
        System.out.println("summed result is : " + number);

    }

    private static int processString(String input) {
        int value = 0;
        for (int i = 0; i < input.length(); i++) {
            value += Integer.parseInt(String.valueOf(input.charAt(i)));
        }
        return value;
    }
}

hope this help..

meka wadada ban???

 

[nagaya]

mama dapu eka athi 1st page eke,eka man test karlama balala damme

 

[amilabanuka]

mata meka C# walin liyala dennakooo??

hey man. simple conversion ekakne thiyennne. sahena dewal samanai oya dekema.

meka wadada ban???

yep. I have tested it. I used recursion.

 

[amila.ela]

hey man. simple conversion ekakne thiyennne. sahena dewal samanai oya dekema.



yep. I have tested it. I used recursion.

machan oka liyala dennakoo???