C/C++ Coding challenges

[Enigma_1]

This thread is for C/C++ programming.
I’ll give you guyz an algorithm. Give me a C/C++ implementation of it. Here goes. Say I have a number 896235716. I need to validate this. Validation algorithm is like this.


From the last digit you start extracting. Here the last digit is 6. So you take number 6. Then you don’t take 1 but you take 7. Likewise extraction goes on.

8 9 6 2 3 5 7 1 6

8 6 3 7 6


multiply all the extracted digits by 2
8X2 = 16
6X2 = 12
3X2 = 6
7X2 = 14
6x2 = 12

Then add all the digits together.
1+6 + 1+2 + 6 + 1+4 + 1+2 = 24

if the total is divisible by 10 then its a valid number.
If 24mod10 !=0 then 896235716 is not a valid number.
say total is 20. Then 20mod10 ==0 so the corresponding number is valid.

Please note that validation number (896235716 in this case) can be varying in length. Extraction always starts from the last digit. If you have doubts on this let me know.

mama example valid number ekak dennum.
5482742451 number eka valid number ekak.

kattiya try ekak danna. good luck.

 

[Enigma_1]

ayyo kauruth meka baraganne nadda

 

[rclakmal]

class ValidTest {

    String number;

    public ValidTest(String number) {
        this.number = number;
    }

    public String testValid() {
        char numbers[] = number.toCharArray();
        String sumWord ="";
        int sum=0;
        for (int i = numbers.length - 1; i >= 0; i -= 2) {
            sumWord+=Integer.parseInt(Character.toString(numbers[i]))*2;
        }
        for(int k=0;k<sumWord.length();k++){
            sum+=Integer.parseInt(Character.toString(sumWord.charAt(k)));
        }

        if (sum % 10 == 0) {
            return "valid";
        } else {
            return "false";
        }
    }

    public static void main(String[] args) {
        System.out.println("Enter your Number");
        String s = new Scanner(System.in).nextLine();
        System.out.println(new ValidTest(s).testValid());
    }
}

C++ wadiya dannaha bro !!! But try ekka denna one !!!

 

[Enigma_1]

java ne. elama thama. ayyo ko anith aya. kauruth na ne.

 

[Enigma_1]

seems like nobody s have a interest on this. anyway here is the code.

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

char* number =NULL;
char temp[2];
int finalval=0;
int tempval =0;
int main()
{
    number =(char*)malloc(1000);
    printf("Please enter the number :");
    scanf("%s",number);

    if(number !=NULL)
    {
        number = number+(strlen(number)-1);
    }
    else
    {
        printf("\nerror on getting the number");
        return -1;
    }

    while(number[0] !='\0')
    {
        temp[0] =number[0];
        tempval = atoi(temp)*2;
        if(tempval>9)
        {
            finalval = (int)(tempval/10)+ tempval%10 + finalval;
        }
        else
        {
            finalval = tempval+finalval;
        }
        number = number-2;
    }

    if(finalval%10 ==0)
    {
        printf("\nThis is a valid number\n");
    }
    else
    {
        printf("\nThis is an invalid number\n");
    }
    system("pause");
    return 0;
}

tested in VS 2008

 

[rclakmal]

kolla uba post karapan thawa problems .........its really helpful !!! Thanks for the code !

 

[Enigma_1]

thx machan. thanks for the encouragement. Above algorithm is use to validate the credit card numbers. I will add another algorithm like this.
Thnkas

 

[Enigma_1]

oky onna next challenge eka. C/C++ program code ekak denna date ekak dunnama (year eka 1899 ta wada wadi date ekak) weekday eka mokakda kiyala denna one.
for an Eg

Please enter the date (dd-mm-yyyy) : 30-07-2010 - user input eka
This day is Friday. - Computer response eka .

 

[Jack_Sparrow]

patta thread eka

 

[hasiwebmail]

oky onna next challenge eka. C/C++ program code ekak denna date ekak dunnama (year eka 1899 ta wada wadi date ekak) weekday eka mokakda kiyala denna one.
for an Eg

Please enter the date (dd-mm-yyyy) : 30-07-2010 - user input eka
This day is Friday. - Computer response eka .

#include<stdio.h>
#include<conio.h>
void main()
{
unsigned int days,year,date,month;
int i,m,sum=0,j,y,od=0;
clrscr();
printf("\nEnter the DATE::");
scanf("%d",&date);
printf("\nEnter the MONTH::");
scanf("%d",&month);
printf("\nEnter the YEAR:: ");
scanf("%d",&year);
y=year-1;
while(1)
{
if(y>400)
y-=400;
else
break;
}
if(y>300)
{
y-=300;
od+=1;
}
else if(y>200)
{
y-=200;
od+=3;
}
else if (y>100)
{
y-=100;
od+=5;
}
od+=(y/4)*2+(y-(y/4));
od=od%7;
for(m=1;m<month;m++)
{
switch(m)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: days=31;
break;
case 4:
case 6:
case 9:
case 11: days=30;
break;
case 2:
{
if(year%4==0 && year%100!=0 || year%400==0)
days=29;
else
days=28;
break;
}
}
sum=sum+days;
}
sum=(sum+date)%7;
od+=sum;
switch(od)
{
case 1rintf("MONDAY");break;
case 2rintf("TUESDAY");break;
case 3rintf("wensdAY");break;
case 4rintf("thusday");break;
case 5rintf("FRIDAY");break;
case 6rintf("SATURDAY");break;
case 7rintf("SUNDAY");break;
}
getch();
}

 

[kasun88888]

Ela ela machan

 

[Rovin]

Maxxa

 

[Dileepa.]

This thread is for C/C++ programming.
I’ll give you guyz an algorithm. Give me a C/C++ implementation of it. Here goes. Say I have a number 896235716. I need to validate this. Validation algorithm is like this.


From the last digit you start extracting. Here the last digit is 6. So you take number 6. Then you don’t take 1 but you take 7. Likewise extraction goes on.

8 9 6 2 3 5 7 1 6

8 6 3 7 6


multiply all the extracted digits by 2
8X2 = 16
6X2 = 12
3X2 = 6
7X2 = 14
6x2 = 12

Then add all the digits together.
1+6 + 1+2 + 6 + 1+4 + 1+2 = 24

if the total is divisible by 10 then its a valid number.
If 24mod10 !=0 then 896235716 is not a valid number.
say total is 20. Then 20mod10 ==0 so the corresponding number is valid.

Please note that validation number (896235716 in this case) can be varying in length. Extraction always starts from the last digit. If you have doubts on this let me know.

mama example valid number ekak dennum.
5482742451 number eka valid number ekak.

kattiya try ekak danna. good luck.

Simple Logic - in C#.net

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace CreditCardValidator
{
    public partial class Form1 : Form
    {
        Int64 l, y,p,x;
        static Int64 tot=0;
        int z = 0;
        public Form1()
        {
            InitializeComponent();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            l = Int64.Parse(txt_cno.Text);
            x = l;
           while (true)
            {
                
                    x = x / 10;
                    y = l % 10;
                    if (z % 2 == 0)
                    {
                        if (y != 0)
                        {
                            p = y * 2;
                            Int64 x1 = p % 10;
                            Int64 x2 = p / 10;
                            tot += x1 + x2;
                        }
                    }
                    z++;
                    if (x == 0)
                        break;

              }
           if (tot % 10 == 0)
               MessageBox.Show("Valid Credit Card Number!");
           else
               MessageBox.Show("Fuker! Enter Valid number !");
           }
        }
    }

 

[Enigma_1]

l = Int64.Parse(textBox1.Text);
            x = l;
           while (true)
            {
                
                    x = x / 10;
                    y = l % 10;
                  [B][COLOR=Red]  l = x;[/COLOR][/B]
                    if (z % 2 == 0)
                    {
                        if (y != 0)
                        {
                            p = y * 2;
                            Int64 x1 = p % 10;
                            Int64 x2 = p / 10;
                            tot += x1 + x2;
                        }
                    }
                    z++;
                    if (x == 0)
                        break;

              }
           if (tot % 10 == 0)
               MessageBox.Show("Valid Credit Card Number!");
           else
               MessageBox.Show("Fuker! Enter Valid number !");

very nice logic machan. but thr is a small bug (I have corrected it.). check the above code. you can track the bug by entering the number 1243 . Thks for the post . ela ma thama

 

[cyber22118]

.. these are baby logics lets do something like face recognition

 

[Dileepa.]

l = Int64.Parse(textBox1.Text);
            x = l;
           while (true)
            {
                
                    x = x / 10;
                    y = l % 10;
                  [B][COLOR=Red]  l = x;[/COLOR][/B]
                    if (z % 2 == 0)
                    {
                        if (y != 0)
                        {
                            p = y * 2;
                            Int64 x1 = p % 10;
                            Int64 x2 = p / 10;
                            tot += x1 + x2;
                        }
                    }
                    z++;
                    if (x == 0)
                        break;

              }
           if (tot % 10 == 0)
               MessageBox.Show("Valid Credit Card Number!");
           else
               MessageBox.Show("Fuker! Enter Valid number !");

very nice logic machan. but thr is a small bug (I have corrected it.). check the above code. you can track the bug by entering the number 1243 . Thks for the post . ela ma thama

Just compiled and posted machan....... not tested !!
Thanks for the correction

 

[Dileepa.]

.. these are baby logics lets do something like face recognition

ok then .... so you start first...

 

[Enigma_1]

#include<stdio.h>
#include<conio.h>
void main()
{
unsigned int days,year,date,month;
int i,m,sum=0,j,y,od=0;
clrscr();
printf("\nEnter the DATE::");
scanf("%d",&date);
printf("\nEnter the MONTH::");
scanf("%d",&month);
printf("\nEnter the YEAR:: ");
scanf("%d",&year);
y=year-1;
while(1)
{
if(y>400)
y-=400;
else
break;
}
if(y>300)
{
y-=300;
od+=1;
}
else if(y>200)
{
y-=200;
od+=3;
}
else if (y>100)
{
y-=100;
od+=5;
}
od+=(y/4)*2+(y-(y/4));
od=od%7;
for(m=1;m<month;m++)
{
switch(m)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12: days=31;
break;
case 4:
case 6:
case 9:
case 11: days=30;
break;
case 2:
{
if(year%4==0 && year%100!=0 || year%400==0)
days=29;
else
days=28;
break;
}
}
sum=sum+days;
}
sum=(sum+date)%7;
od+=sum;
switch(od)
{
case 1rintf("MONDAY");break;
case 2rintf("TUESDAY");break;
case 3rintf("wensdAY");break;
case 4rintf("thusday");break;
case 5rintf("FRIDAY");break;
case 6rintf("SATURDAY");break;
case 7rintf("SUNDAY");break;
}
getch();
}

ela kiri ne. thx machan post ekata. . mage version ekath mama dannum.

 

[deegopower]

maxxa thread.......

 

[croshanlg]

CoOOoL thread bro(hope u r a bro.. ).. keep it up...

May I give u an idea..?? why don't you expand this thread to other languages also, like Java, VB and some scripting languages (PHP is my fav.)

I think it will be great for all the people who stick with different kinds languages.

And mind you.. it will attract many people (who r doin some sort of programming or IT related studies) towards Elakiri...


It will definitely attract the IT students who desperately look for solutions and clues for their assignment.
GT will be very grateful to you for new members..

+ rep..